Ta co \(\frac{33.10^3}{2^3.10^3+7000}=\frac{33.10^3}{8.10^3+7.10^3}=\frac{33.10^3}{15.10^3}=\frac{33}{15}>\frac{3774}{5217}\)

u3hfhfhfjjfjfjFegyvdydvvydcvyvyddvvdvyrvvyvrbrvyfvybrv bbcbfbfbchrubdvh dvubudvbudvbvudbudvbudvubevbudvbudvubdvbduburvubrvubrvubruvbubrvburvbururvubvrbyrvbu  jjfhfhvhvvhvhvhhfhffhjvjf(&h&7

\(\frac{33.10^3}{2^3.5.10^3+7000}=\frac{33.10^3}{2^3.5.10^3+7.10^3}=\frac{33.10^3}{10^3\left(2^3.5+7\right)}=\frac{33}{8.5+7}=\frac{33}{47}\)

\(\frac{3774}{5217}=\frac{3774:111}{5217:111}=\frac{34}{47}\)

Vì \(\frac{33}{47}< \frac{34}{47}\Rightarrow\frac{33.10^3}{2^3.5.10^3+7000}< \frac{3774}{5217}\)

\(\frac{33.10^3}{2^3.5.10^3+7000}=\frac{33.10^3}{8.5.10^3+7.10^3}\)

=\(\frac{33.10^3}{10^3\left(40+7\right)}=\frac{33}{47}\)

\(\frac{3774}{5217}=\frac{111.34}{111.47}=\frac{34}{47}\)

Vậy: \(\frac{3774}{5217}>\frac{33.10^3}{2^3.5.10^3+7000}\)

\(\frac{33.10^3}{2^3.5.10^3+7000}=\frac{33.10^3}{40.10^3+7.10^3}=\frac{33.10^3}{10^3.47}=\frac{33}{47}\)

\(\frac{3774}{5217}=\frac{34}{47}\)

Do đó VT<VP

33.10³/2³.5.10³+7000<3774/5217