\(\frac{25}{42}—\frac{20}{63}\)
\(\frac{9}{50}-\frac{13}{75}\)
\(\frac{2}{19}-\frac{2}{65}-\frac{4}{39}\)
tính chi tiết :
a,\(\frac{25}{42}-\frac{20}{63}\)
b,\(\frac{9}{50}-\frac{13}{75}-\frac{1}{6}\)
c,\(\frac{2}{15}+\frac{-2}{65}-\frac{4}{39}\)
Các bạn lm chi tiết hộ mình vs thank nha ^~^
a,\(\frac{25}{42}-\frac{20}{63}=\frac{5}{18}\)
b,\(\frac{9}{50}-\frac{13}{75}-\frac{1}{6}\)
=\(\frac{1}{150}-\frac{1}{6}\)
=\(-\frac{4}{25}\)
c,\(\frac{2}{15}+\frac{-2}{65}-\frac{4}{39}\)
=\(\frac{32}{195}-\frac{4}{39}\)
=\(\frac{4}{65}\)
a,=75/126-40/126=35/126=5/18
b,=27/150-26/150-25/150=-4/25
c,=26/195+-6/195-20/195=0
1) Tính
a)\(\frac{25}{42}\)-\(\frac{20}{63}\)
b)\(\frac{9}{50}\)-\(\frac{13}{75}\)-\(\frac{1}{6}\)
c)\(\frac{2}{15}\)-\(\frac{2}{65}\)-\(\frac{4}{39}\)
2/Tìm x, biết
a) x+\(\frac{7}{12}\)=\(\frac{17}{18}\)-\(\frac{1}{9}\)
b)\(\frac{29}{30}\)-(\(\frac{18}{23}\)+x) =\(\frac{7}{69}\)
Bài1
a) 25/42 - 20/63 =5/18
b) 9/50 - 13/75 - 1/6 = -4/25
c) 2/15 - 2/65 - 4/39 = 0
Bài2
a) x + 7/12 =17/18-1/9 b) 29/30 - (18/23 + x)=7/69
x + 7/12 = 5/6 18/23 + x =29/30 - 7/69
x =5/6 - 7/12 18/23 +x = 199/230
x = 1/4 x = 199/230 - 18/23
x= 19/230
\(A=5,3:\left(5\frac{5}{28}-2\frac{13}{36}+1\frac{16}{63}\right)\)
\(B=\left(\frac{19}{10}\times\frac{19}{10}+\frac{39}{2}:\frac{13}{3}\right)\times\left(\frac{62}{75}-\frac{12}{75}\right)\)
\(A=\frac{-7}{25}.\frac{39}{-14}.\frac{50}{78}\)
\(B=\frac{-3}{11}.\frac{-22}{66}.\frac{121}{15}\)
\(C=\frac{3}{7}.\frac{2}{5}.\frac{7}{3}.20.\frac{19}{72}\)
\(D=\frac{6}{7}.\frac{8}{13}+\frac{9}{13}.\frac{6}{7}-\frac{4}{13}.\frac{6}{7}\)
Tính giá trị biểu thức
bài 1 tính
A = \(\frac{25}{54}\)+\(\frac{3}{75}\):\(\frac{\left(\frac{39}{65}+0,415-\frac{33}{600}\right):\frac{21}{9}}{7^2-15,25+13\frac{15}{36}-16\frac{17}{9}}\)
bài 2 tính ti số \(\frac{A}{B}\)biết : \(A=\frac{4}{7.13}+\frac{6}{7.41}+\frac{9}{10.41}++\frac{7}{10.57}\)
\(B=\frac{7}{19.31}+\frac{5}{19.43}+\frac{3}{23.43}+\frac{11}{23.57}\)
A=\(1-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}+\frac{19}{90}-\frac{21}{110}+\frac{23}{132}-\frac{25}{156}\)\(\frac{25}{156}\)
Giups mình nha !!!
Đè thừa một số \(\frac{25}{156}\),mk ko lại đề bài nhé
\(A=1-\frac{2+3}{2\cdot3}+.....+\frac{11+12}{11\cdot12}-\frac{12+13}{12\cdot13}\)
\(=1-\frac{1}{2}-\frac{1}{3}+\frac{1}{3}+\frac{1}{4}-...+\frac{1}{11}+\frac{1}{12}-\frac{1}{12}-\frac{1}{13}\)
\(=\frac{1}{2}-\frac{1}{13}=\frac{11}{26}\)
\(\frac{2}{6} + \frac{9}{20} - \frac{11}{30} + \frac{13}{42} - \frac{15}{56} + \frac{17}{72} - \frac{19}{90} + \frac{21}{110} - \frac{23}{132}\)
tính A=\(\frac{\frac{2}{39}-\frac{1}{15}-\frac{2}{153}}{\frac{1}{85}+\frac{3}{50}+\frac{3}{65}}:\frac{1+\frac{2}{71}-\frac{5}{121}}{\frac{65}{121}-\frac{26}{71}-13}\)
tính giá trị:
A=\(\frac{5}{6}-\frac{-1}{12}+\frac{2}{3}-\frac{-2}{7}+\frac{1}{25}-\frac{-1}{4}-\frac{5}{42}\)
B=\(\frac{7.6^{10}.2^{20}.3^6-2^{19}.6^{15}}{9.6^{19}.2^9-4.3^{17}2^{26}}\)