(\(\frac{1}{99}\)+ \(\frac{12}{999}\)- \(\frac{123}{9999}\)) . ( \(\frac{1}{2}\)- \(\frac{1}{3}\)-\(\frac{1}{6}\))
Những câu hỏi liên quan
tính nhanh:
B=(\(\frac{1}{99}+\frac{12}{999}-\frac{123}{9999}\)).(\(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\))
Ta có: B= (1/99+12/999-123/9999).(1/2-1/3-1/6)
B= (1/99+12/999-123/9999).(3/6-2/6-1/6)
B= (1/99+12/999-123/9999).0
B= 0
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B = (1/99+12/999-123/9999).(1/2-1/3-1/6)
B= (1/99+12/999+123/9999).0
B=0
tk mình nha !
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tính nhanh\(\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)x\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)\)
tính giá trị :\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\text{ }\)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0\)
\(Q=0\)
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Q=(1/99+12/999+123/999).(1/2-1/3-1/6) =(1/99+12/999+123/999).0 Q=0
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\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(\Leftrightarrow Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\times0\)
\(\Leftrightarrow Q=0\)
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Xem thêm câu trả lời
Tinh gia tri bieu thuc :
\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0\)
\(=0\)
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\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)=\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right).0=0\)
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Thực hiện phép tính :
a, \(\frac{5922.6001-69}{5932+6001.5931}\)
b, \(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}+\frac{1234}{99999}\right).\left(\frac{1}{2}_{ }-\frac{1}{3}-\frac{1}{6}\right)\)
\(A=\left(\frac{9}{1999}+\frac{99}{999}+\frac{999}{9999}\right)\cdot\left(\frac{1}{5}-\frac{1}{4}+\frac{1}{20}\right)\)
A=(9/1999+99/999+999/9999).(1/5-1/4+1/20)
A=(9/1999+99/999+999/9999).(-1/20+1/20)
A=(9/1999+99/999+999/9999).0
A=0
Vì mọi số nhân vs 0 thì đều = 0 kể cả phân số
mk nhanh nhất ủng hộ nha
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\(A=\left(\frac{9}{1999}+\frac{99}{999}+\frac{999}{9999}\right)\cdot0\)
A=0
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1/Tính nhanh:
A= \(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+...+\frac{1}{9999}\)
2/Tính tổng:
A=\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)
1/
A= 1/15+1/35+1/63+1/99+ ... + 1/9999
A=1/3.5+1/5.7+1/7.9+ ... +1/99.101
2A=2/3.5+2/5.7+2/7.9+ ... +2/99.101
2A=1/3-1/5+1/5-1/7+1/7-1/9+ ... + 1/99-1/101
2A=1/3-1/101
A=49/303
Sai thì thôi nhé
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A= 1/1.2+1/2.3+1/3.4+1/4.5+1/5.6+1/6.7
A=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
A=1-1/7
A=6/7
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Aleft(1frac{1}{6}timesfrac{6}{7}times6:frac{3}{5}right):left(4frac{1}{5}timesfrac{10}{11}+5frac{2}{10}right)B1frac{13}{15}times25%times3+left(frac{8}{15}-frac{79}{60}right):1frac{23}{4}Cfrac{123}{4567}timesfrac{1}{8}+frac{123}{4567}timesfrac{1}{2}-frac{123}{4567}timesfrac{13}{8}Dfrac{10frac{1}{3}timesleft(24frac{1}{2}-15frac{6}{7}right)-frac{12}{11}timesleft(frac{10}{3}-1,75right)}{left(frac{5}{9}-0,25right)timesfrac{60}{11}+194frac{8}{99}}
Đọc tiếp
\(A=\left(1\frac{1}{6}\times\frac{6}{7}\times6:\frac{3}{5}\right):\left(4\frac{1}{5}\times\frac{10}{11}+5\frac{2}{10}\right)\)
\(B=1\frac{13}{15}\times25\%\times3+\left(\frac{8}{15}-\frac{79}{60}\right):1\frac{23}{4}\)
\(C=\frac{123}{4567}\times\frac{1}{8}+\frac{123}{4567}\times\frac{1}{2}-\frac{123}{4567}\times\frac{13}{8}\)
\(D=\frac{10\frac{1}{3}\times\left(24\frac{1}{2}-15\frac{6}{7}\right)-\frac{12}{11}\times\left(\frac{10}{3}-1,75\right)}{\left(\frac{5}{9}-0,25\right)\times\frac{60}{11}+194\frac{8}{99}}\)
Tính:
\(\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right).\left(\frac{1}{5}-\frac{1}{7}-\frac{2}{35}\right)\)
\(\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right)\left(\frac{1}{5}-\frac{1}{7}-\frac{2}{35}\right)\)
\(=\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right)\left(\frac{7}{35}-\frac{5}{35}-\frac{2}{35}\right)\)
\(=\left(\frac{99^9}{11^9}-\frac{99^{99}}{11^{99}}-\frac{99^{999}}{11^{999}}\right).0\)
\(=0\)
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bài dễ thế không ai làm được hay thật
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