`(-3737)/(4141)=(-37xx101)/(41xx101)=(-37)/41`

Vì `37/41>34/41`

`=>(-37)/41<(-34)/41`

Hay `(-3737)/(4141)<(-34)/41`

\(\dfrac{-3737}{4141}=\dfrac{-37\cdot101}{41\cdot101}=\dfrac{-37}{41}\)

Mà \(\dfrac{-37}{41}< \dfrac{-34}{41}\) (vì \(-37< -34\))

Nên \(\dfrac{-3737}{4141}< \dfrac{-34}{41}\)

`143/132=(143:11)/(132:11)=13/12`

`3535/3737=(3535:101)/(3737:101)=35/37`

a. \(\dfrac{13}{12}\)

b. \(\dfrac{35}{37}\)

13/12 ; 35/37

Câu đầu: Chia phân số thứ 2 cho 101, phân số thứ 3 cho10101. Kết quả bằng 25/53

Câu sau;

Chia phân số đầu cho 10101, kết quả dc 25/53

3737/4141=37/41(chiaa cho 101)

Mà 2 phân số sau ko bằng nhau

an khánh bạn trả lời đi còn nói ai 

mình nhầm bạn nguyen gia

3737.(12x-91)=37

=> 12x-91=3737:37=101

=> 12x=101+91=192

=> x=192:12=16

a) \(A=\dfrac{3737.43-4343.37}{2+4+6+...+2018}\)

\(\Leftrightarrow A=\dfrac{3737.43-43.101.37}{2+4+6+...+2018}\)

\(\Leftrightarrow A=\dfrac{3737.43-43.3737}{2+4+6+...+2018}\)

\(\Leftrightarrow A=\dfrac{0}{2+4+6+...+2018}\)

\(\Leftrightarrow A=0\)

b) \(B=\dfrac{101+100+99+...+3+2+1}{101-100+99-98+...+3-2+1}\)

\(\Leftrightarrow B=\dfrac{\left(101+1\right).101:2}{\left(101+99+97+...+1\right)-\left(100+98+96+...+2\right)}\)

\(\Leftrightarrow B=\dfrac{5151}{\left[\left(101+1\right).51:2\right]-\left[\left(100+2\right).50:2\right]}\)

\(\Leftrightarrow B=\dfrac{5151}{2601-2550}\)

\(\Leftrightarrow B=\dfrac{5151}{51}\)

\(\Leftrightarrow B=101\)

\(45.\left(\frac{7373}{3030}+\frac{7373}{4242}+\frac{7373}{5656}+\frac{7373}{7272}\right)\)

\(=45.\left(\frac{101.73}{101.30}+\frac{101.73}{101.42}+\frac{101.73}{101.56}+\frac{101.73}{101.72}\right)\)

\(=45.\left(\frac{73}{30}+\frac{73}{42}+\frac{73}{56}+\frac{73}{72}\right)\)

\(=45.\left(\frac{73}{5.6}+\frac{73}{6.7}+\frac{73}{7.8}+\frac{73}{8.9}\right)\)

\(=45.73.\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\right)\)

\(=45.73.\left(\frac{1}{5}-\frac{1}{9}\right)\)

\(=45.73.\frac{4}{45}\)

\(=73.4\)

\(=292\)

\(\frac{2}{7}\)x  \(\left(\frac{707}{202}+\frac{707}{3030}+\frac{707}{4242}+\frac{707}{5656}+\frac{707}{7272}\right)\)

\(=\frac{2}{7}\)x   \(\left(\frac{7}{2}+\frac{7}{30}+\frac{1}{6}+\frac{1}{8}+\frac{7}{72}\right)\)

\(=\frac{2}{7}\)x    \(\left(\frac{1260}{360}+\frac{84}{360}+\frac{60}{360}+\frac{45}{360}+\frac{35}{360}\right)\)

\(=\frac{2}{7}\)x   \(\frac{371}{90}=\frac{53}{45}\)

3737×63-6363×37

=(37×101)×63-(63×101)×37

=0

0/1+2+3+....+2006

Xét dãy 1; 2;3;...;2006

Dãy trên có 2006-1+1=2006 ( số hạng)

Suy ra dãy trên có 2006:2=1003 cặp

Có 0/1+2+3+...+2006 ( 2006 số )

=0/(1+2006)+(2+2005)+(3+2004)+.... ( 1003 cặp)

=0/2007+2007+2007+...... ( 1003 số)

=0/2007×1003

=0/2013021

=0

Gọi tử số là A , mẫu số là B

Xét tử số 

A = 3737.63-6363.37

A = 37 .101 . 63 -6363 . 37

A = ( 63 . 101 ) 37 - 6363 . 37

A = 6363 . 37 - 6363 . 37

A= 0

=> A/B = 0/B = 0

\(\frac{3737.63-6363.37}{1+2+3+......+2006}=\frac{37.101.63-63.101.37}{2007.2006\div2}=\frac{1}{4026042\div2}=\frac{1}{2013021}\)