\(\dfrac{1997\times1996-1}{1995\times1997+1996}\)

= \(\dfrac{1997\times\left(1995+1\right)-1}{1995\times1997+1996}\)

= \(\dfrac{1997\times1995+1997-1}{1995\times1997+1996}\)

= \(\dfrac{1995\times1997+1996}{1995\times1997+1996}\)

= 1

a/ Gọi A là giá trị của biểu thức trên

\(\Rightarrow A=\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+\frac{1}{120}\)

\(\Rightarrow A=\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+...+\frac{2}{240}\)

\(\Rightarrow A=2\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{240}\right)\)

\(\Rightarrow\frac{A}{2}=\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{240}\)

\(\Rightarrow\frac{A}{2}=\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{14.15}+\frac{1}{15.16}\)

\(\Rightarrow\frac{A}{2}=\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{16}\)

\(\Rightarrow\frac{A}{2}=\frac{1}{4}-\frac{1}{16}\)

\(\Rightarrow A=\frac{3}{16}.2=\frac{3}{8}\)

b/  0,2 x 317 x 7 + 0,14 x 3520 + 33,1 x 14

= 0,2 x 317 x 7 : 10 x 10    +     0,14 x 3520    +    33,1 x 100 x  14 : 100

= 0,2 x 317 x 0,7 x 10   + 0,14 x 3520   + 33,1 x 100 x 0,14

= ( 0,2 x 0,7) x 317 x 10   + 0,14 x 3520  + 3310 x 0,14

= 0,14 x 3170  +  0,14 x 3520   + 3310 x 0,14

= 0,14   x ( 3170 + 3520 + 3310)

= 0,14  x10000 

= 1400

Hứa r, k mik nha!

1400 đúng 100%

nếu là (-1997*1996 + 1)/(-1995*1997 +1996) thì:

(-1997*1996+1)/(-1997*1995+1997-1)=(-1997*1996+1)/(-1997*1996-1)

  \(\frac{\left(72\times1995-1996\right)\times\left(18-36\div2\right)\times\left(148\div5-7\right)}{1+3+5+...+1993+1995}\)

= \(\frac{\left(72\times1995-1996\right)\times\left(18-18\right)\times\left(148\div5-7\right)}{1+3+5+...+1993+1995}\)

= \(\frac{\left(72\times1995-1996\right)\times0\times\left(148\div5-7\right)}{1+3+5+...+1993+1995}\)

= \(\frac{0}{1+3+5+...+1993+1995}\)

= 0 : (1 + 3 + 5 + ... + 1993 + 1995)

= 0

(72x1995-1996)x(18-36:2)x(148:5-7) / 1+3+5+....+1993+1995

=(72x1995-1996)x0x(148:5-7) / 1+3+5+...+1993+1995

=0 / 1+3+5+...+1993+1995

=0

Tích nha