A=\(\frac{-41000}{973}\)

\(-\frac{2000}{139}\)

                                                    Giải:         

Đặt \(A=13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6},B=1\frac{3}{7}+\frac{10}{3},C=12\frac{1}{3}-14\frac{2}{7}\)

Ta có:             

\(A=13-2-10+\frac{1}{4}-\frac{5}{27}-\frac{5}{6}=1+\frac{27-20-90}{108}=1-\frac{83}{108}=\frac{25}{108}\)              

\(A.230\frac{1}{5}=\frac{25}{108}.230\frac{1}{25}=\frac{25}{108}.\frac{5751}{25}=\frac{5751}{108}=\frac{213}{4}\)                        

\(A.230\frac{1}{25}+46\frac{3}{4}=\frac{213}{4}+\frac{187}{4}=100\)                     

\(B=1+\frac{3}{7}+3+\frac{1}{3}=4+\frac{3}{7}+\frac{1}{3}=4+\frac{16}{21}=\frac{100}{21}\)                               

\(C=12\frac{1}{3}-14\frac{2}{7}=12-14+\frac{1}{3}-\frac{2}{7}=-2+\frac{7-6}{21}=-\frac{41}{21}\)            

\(B:C=\frac{100}{21}:\left(-\frac{41}{21}\right)=-\frac{100}{41}\)                

\(E=\frac{A.230\frac{1}{25}+46\frac{3}{4}}{B:C}=\frac{100}{-\frac{100}{41}}=-41\)

giup minh vs

Đặt : \(A=\frac{\left[13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right]\cdot230\frac{1}{25}+46\frac{3}{4}}{\left[1\frac{3}{10}+\frac{10}{3}\right]:\left[12\frac{1}{3}-14\frac{2}{7}\right]}\)

\(A=\frac{\left[\frac{53}{4}-\frac{59}{27}-\frac{65}{6}\right]\cdot\frac{5751}{25}+\frac{187}{4}}{\left[\frac{13}{10}+\frac{10}{3}\right]:\left[\frac{37}{3}-\frac{100}{7}\right]}\)

\(A=\frac{\left[\frac{1431}{108}-\frac{236}{108}-\frac{1170}{108}\right]\cdot\frac{5751}{25}+\frac{187}{4}}{\left[\frac{39}{30}+\frac{100}{30}\right]:\left[\frac{259}{21}-\frac{300}{21}\right]}\)

\(A=\frac{\frac{25}{108}\cdot\frac{5751}{25}+\frac{187}{4}}{\frac{139}{30}:\left[-\frac{41}{21}\right]}\)

\(A=\frac{\frac{5751}{108}+\frac{187}{4}}{\frac{139}{30}\cdot\left[-\frac{21}{41}\right]}\)

\(A=\frac{\frac{5751}{108}+\frac{5049}{108}}{-\frac{973}{410}}=\frac{100}{-\frac{973}{410}}=-\frac{41000}{973}\)

thank you huynh quang sang