a, Có : (1/60)^200 = [(1/2)^4]^200 = (1/2)^800

Vì 0 < 1/2 < 1 nên (1/2)^800 > (1/2)^1000

=> (1/16)^200 > (1/2)^1000

Tk mk nha

a) \(\left(\frac{1}{16}\right)^{200}=\left(\frac{1}{2}\right)^{800}< \left(\frac{1}{2}\right)^{1000}\)

a) \(\left(\frac{1}{16}\right)^{200}=\frac{1}{16^{200}}\)

\(\left(\frac{1}{2}\right)^{1000}=\frac{1}{2^{1000}}\)

có : \(16^{200}=\left(2^4\right)^{200}=2^{800}\)

ta thấy \(2^{800}< 2^{1000}\)

\(\Rightarrow16^{200}< 2^{1000}\)

\(\Rightarrow\frac{1}{16^{200}}>\frac{1}{2^{1000}}\)

\(\Rightarrow\left(\frac{1}{16}\right)^{200}>\left(\frac{1}{2}\right)^{100}\)

xét A và B,ta thấy:

20/39>14/39

22/27>22/29

18/43<18/41

Ta có: 20/39+22/27>14/39+22/29

2012^2013+2013^2013<2013^2013+2013^2014

xet A va B ta thay:

20/39>14/39

22/27>22/29

18/43<18/41

vay A>B

mik biết nhưng ko nói

hồ trần nhi nói rứa thì coi như ko biết còn gì nữa

giải đi mà mấy bạn

a, \(3^{400}=\left(3^4\right)^{100}=81^{100}\)

\(4^{300}=\left(4^3\right)^{100}=64^{100}\)

vì \(81^{100}>64^{100}\)

suy ra 3^400 > 4^300

b,  \(9^{32}=\left(3^2\right)^{32}=3^{64}\)

\(27^{25}=\left(3^3\right)^{25}=3^{75}\)

vì  \(3^{64}< 3^{75}\)

suy ra 9^32 < 27^25

c,   có 2 ^2999 < 2^3000 = \(\left(2^3\right)^{1000}=8^{1000}\)

có 3^2001> 3^2000 = \(\left(3^2\right)^{1000}=9^{1000}\)

vì 8^1000 <9^1000

suy ra 2^2999<3^2001

tk mk nhé

3 ^ 400 = 3 ^ 4 x 100 = ( 3^4 ) ^ 100 = 81 ^ 100

4 ^ 300 = 4 ^ 3 x 100 = ( 4 ^ 3 ) ^ 100 = 64 ^ 100

Vì 81 > 64 nên 3^ 400 > 4 ^ 300

Mấy câu kia tương tự nha

a) 3^400 < 4^300

b) 9^32 < 27^25

c) 2^29999 > 3^2001

k mk nha

mk làm lộn rồi a là > nha

Ta có: \(\dfrac{20}{39}>\dfrac{20}{41}>\dfrac{18}{41}\left(1\right)\)

\(\dfrac{22}{27}>\dfrac{22}{29}\left(2\right)\)

\(\dfrac{18}{43}=1-\dfrac{25}{43};\dfrac{14}{39}=1-\dfrac{25}{39}\)

Vì \(\dfrac{25}{43}< \dfrac{25}{39}\Rightarrow1-\dfrac{25}{43}>1-\dfrac{25}{39}\Rightarrow\dfrac{18}{43}>\dfrac{14}{39}\left(3\right)\)

Từ \(\left(1\right);\left(2\right);\left(3\right)\) ta suy ra : A>B

a. \(27^{11}=\left(3^3\right)^{11}=3^{3\cdot11}=3^{33}\)
\(81^8=\left(3^4\right)^8=3^{4\cdot8}=3^{32}\)
Vì 32<33 => 3³²<3³³ => 81⁸<27¹¹
b. \(63^{15}=\left(63^5\right)^3=992436543^3\)
\(34^{18}=\left(34^6\right)^3=1544804416^3\)
Vì 992436543<1544804416 nên 992436543³<1544804416³ => \(63^{15}< 34^{18}\)