rút gọn các phép tinh sau
\(\frac{23.5-23}{4-27};\frac{1717-101}{2828+204}\)
Rút gọn
23.5- 23/4- 27
Nếu đề là \(\frac{23.5-23}{4-27}\) thì ok :v
\(\frac{23.5-23}{4-27}=\frac{23.5-23}{-23}=\frac{23.\left(5-1\right)}{-23}=\frac{23.4}{-23}=\frac{92}{-23}\)
rút gọn phân số
23 - 23.5
4-27
23-23.5 phần 4-27=23.(1-5)phần -23=23.-4 phần -23=-23.4 phần -23=4
Đáp số 4
rút gọn
\(\frac{23.5-23}{4-27}\)
\(\frac{23.5-23}{4-27}\)=\(\frac{23.\left(5-1\right)}{-23}\)=\(\frac{92}{-23}\)
rút gọn
\(\frac{23.5-23}{4-27}\);
\(\frac{2130-15}{3550-25}\);
\(\frac{1717-101}{2828-404}\)
a; \(\dfrac{9}{27}\) + \(\dfrac{7}{-49}\)
= \(\dfrac{1}{3}\) - \(\dfrac{1}{7}\)
= \(\dfrac{7}{21}\) - \(\dfrac{3}{21}\)
= \(\dfrac{4}{21}\)
b; - \(\dfrac{12}{10}\) + \(\dfrac{-25}{30}\)
= - \(\dfrac{6}{5}\) - \(\dfrac{5}{6}\)
= -\(\dfrac{36}{30}\) - \(\dfrac{25}{30}\)
= \(\dfrac{-61}{30}\)
c; \(\dfrac{-20}{35}\) + \(\dfrac{-16}{-24}\)
= - \(\dfrac{4}{7}\) + \(\dfrac{2}{3}\)
= - \(\dfrac{12}{21}\) + \(\dfrac{14}{21}\)
= \(\dfrac{2}{21}\)
d; - \(\dfrac{21}{77}\) + \(\dfrac{10}{-35}\)
= - \(\dfrac{3}{11}\) - \(\dfrac{2}{7}\)
= - \(\dfrac{21}{77}\) - \(\dfrac{22}{77}\)
= - \(\dfrac{43}{77}\)
1.Thực hiện các phép tính sau (Hợp lý nếu có thể) :
a) 125.(-61).(-2)3.(-1)2016
b) 525-(295-155)-[-145+1155-(-525)]
c) 374.(3-126)-126.(-374)
d)-81+(-5)3.34-(-9)2.(-26)
2. Rút gọn thành phân số tối giản:
a. -45/81
b. 23-23.5/4-27
c.14.25-14.8/17.13+17.15
d. 246246/369369
e. -13.8-16.5/8.(-6)-4.8
Bài 1 Rút gọn
a)2.5.23/46.12
b)23.5-23/4-27
c)2130-15/3550-25
d)1717-101/2828+404
e)4116-14/1029-35
f)2929-101/2.1919+404
a)sắp xếp các số sau theo thứ tự tăng dần:-53;7;-25;0;15;53;-7;-2015
b)rút gọn rồi so sánh:A=3.4+3.7/6.5+24;B=23.5-23/46+3.23
Rút gọn:
a.\(\frac{2.7.13}{26.35}\)
b.\(\frac{3.5.11.13}{33.35.37}\)
c.\(\frac{23.5-23}{4-27}\)
d.\(\frac{1717-101}{2828+404}\)
a) \(\frac{2.7.13}{26.35}=\frac{2.7.13}{2.13.7.5}=\frac{1}{5}\)
b) \(\frac{3.5.11.13}{33.35.37}=\frac{3.5.11.13}{3.11.7.5.37}=\frac{13}{259}\)
c) \(\frac{23.5-23}{4-27}=\frac{23.\left(5-1\right)}{-23}=\frac{4}{-1}=-4\)
d) \(\frac{1717-101}{2828+404}=\frac{101.17-101}{404.7+404}=\frac{101.\left(17-1\right)}{404.\left(7+1\right)}=\frac{101.16}{404.8}=\frac{101.2.8}{101.4.8}=\frac{1}{2}\)