\(\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+2018}\)

\(=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+...+\frac{2}{2018.2019}\)

\(=2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{2018.2019}\right)\)

\(=2\left(\frac{3-2}{2.3}+\frac{4-3}{3.4}+\frac{5-4}{4.5}+...+\frac{2019-2018}{2018.2019}\right)\)

\(=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{2018}-\frac{1}{2019}\right)\)

\(=2\left(\frac{1}{2}-\frac{1}{2019}\right)\)

\(=\frac{2017}{2019}\)

Đặt A=1+1/3+1/6+1/10+ ... + 1/45

1/2.A=1/2+1/6+1/12+1/20+ ... + 1/90

1/2.A= 1/1.2+1/2.3+1/3.4+1/4.5+ ... + 1/9.10

1/2A= 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+ ... +1/9-1/10

1/2.A= 1-1/10

1/2.A=9/10

A=(9/10).2

A=9/5

Sai thì thôi đấy 

bài này lớp 4 mà mình không làm được nhỉ . mình học dốt dốt quá .

(-3/4+2/3);5/11+(-1/4+1/3):5/11

=-1/12:5/11+1/12:5/11

=(-1/12:+1/12):5/11

=0:5/11=0

a, 6/5

b,1

\(A=\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}+...+\dfrac{1}{18.19.20}\)

\(2A=\dfrac{3-1}{1.2.3}+\dfrac{4-2}{2.3.4}+\dfrac{5-3}{3.4.5}+...+\dfrac{20-18}{18.19.20}=\)

\(=\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}+...+\dfrac{1}{18.19}-\dfrac{1}{19.20}=\dfrac{1}{2}-\dfrac{1}{19.20}\)

\(\Rightarrow A=\left(\dfrac{1}{2}-\dfrac{1}{19.20}\right):2\)

AI GIÚP MÌNH VỚI MÌNH ĐANG CẦN GẤP

1/3+1/6+1/12+1/24=8/24+4/24+2/24+1/24=15/24=5/8

tk cho mk nha!

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}=\frac{8}{24}+\frac{4}{24}+\frac{2}{24}+\frac{1}{24}=\frac{15}{24}=\frac{5}{8}\)

\(\frac{5}{8}\)

~Hok tốt~

Gọi biểu thức trên là \(A\)

\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}\)

\(2A=\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}\right)\times2\)

\(2A=\frac{1}{2}\times2+\frac{1}{4}\times2+\frac{1}{8}\times2+\frac{1}{16}\times2+...+\frac{1}{512}\times2\)

\(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{128}\)

\(2A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{128}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\right)\)

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{128}-\frac{1}{256}\)

\(A=1-\frac{1}{256}\)

\(A=\frac{255}{256}\)

thank you bạn