1.(11/12+11/23+11/23+11/24+...+11/89+11/100)+x=5/3

1.(11/12+11/100)+x=5/3

77/75+x=5/3

x=5/3-77/75

x=16/25
 

de ot

=> ( 11/12+ 1/12- 1/23+ 1/23- 1/34+...+ 1/89-1/100 ) +x=5/3

=> (11/12+ 1/12-1/100 ) + x=5/3

=> (11/12+ 11/150) + x=5/3

=>99/100 +x = 5/3

=> x = 5/3 - 99/100

=> x= 203 / 300

K dung NHA

Ta có : (\(\frac{11}{12}+\frac{11}{12\times23}+\frac{11}{23\times34}+...+\frac{11}{89\times100}\)) + x =\(\frac{5}{3}\)

=> (\(\frac{11}{1\times12}+\frac{11}{12\times23}+\frac{11}{23\times34}+...+\frac{11}{89\times100}\)) + x =\(\frac{5}{3}\)

=> (\(1-\frac{1}{12}+\frac{1}{12}-\frac{1}{23}+\frac{1}{23}-\frac{1}{34}+...+\frac{1}{89}-\frac{1}{100}\)) + x =\(\frac{5}{3}\)

=> (\(1-\frac{1}{100}\)) + x =\(\frac{5}{3}\)

=> \(\frac{99}{100}\)+ x =\(\frac{5}{3}\)

=> x = \(\frac{5}{3}-\frac{99}{100}=\frac{203}{300}\)

Vậy x = \(\frac{203}{300}\)

D=115/132/103/132=115/103

\(D=\frac{\frac{88}{132}-\frac{33}{132}+\frac{60}{132}}{\frac{55}{132}+\frac{132}{132}-\frac{84}{132}}\)

\(D=\frac{\frac{115}{132}}{\frac{103}{132}}\)

\(D=\frac{115}{103}\)

D = \(\frac{115}{103}\)

:):):):):):):):):):):):):):):):) mình đâu có biết!

=> 1/11 - 1/13 + 1/13 - 1/15 + ..... + 1/19 - 1/21 - x + 4 + 221/231 = 7/3

=> 1/11 - 1/21 - x + 4 + 221/231 = 7/3

=> 2099/420 - x = 7/3

=> x = 2099/420 - 7/3 = 373/140

Tk mk nha

Bài làm

\(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11.13}+\frac{1}{13.15}+...+\frac{1}{19.21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11}-\frac{1}{21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2.\frac{10}{231}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow\frac{20}{231}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}+\frac{221}{231}=\frac{539}{231}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}=\frac{539}{231}-\frac{221}{231}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}=\frac{318}{231}\)

\(\Leftrightarrow\frac{20}{231}-x=\frac{318}{231}-\frac{924}{231}\)

\(\Leftrightarrow\frac{20}{231}-x=-\frac{606}{231}\)

\(\Leftrightarrow x=\frac{20}{231}-\frac{606}{231}\)

\(\Leftrightarrow x=-\frac{586}{231}\)

Vậy \(\Leftrightarrow=-\frac{586}{231}\)

ta có : 2/11*15 +2/13*15+...+2/19*21 - x +4+221/231=7/3

=>(1/11 -1/13 + 1/13-1/15+...+1/19 - 1/21)-x+4 +221/231=7/3

<=>(1/11 - 1/21)-x+4 + 221/231=7/3

<=>10/231 -  x+4 +221/231 =7/3

<=>1-x +4=7/3

<=>x+4=1-7/3

<=>x+4=-4/3

<=>x=-4/3-4

<=>x=-16/3

vậy x=-16/3

Trước hết tính tổng :

\(\frac{11}{12}+\frac{11}{12\times13}+...+\frac{11}{89\times100}=1-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{89}-\frac{1}{100}\)

\(=1-\frac{1}{100}=\frac{99}{100}\)

Do đó \(\frac{99}{100}+x=\frac{5}{3}\)

Vậy \(x-\frac{5}{3}-\frac{99}{100}=\frac{500-297}{300}=\frac{203}{300}\)

Vậy...

bang 112222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222233333333333333333333333356152784327152718452314983254623145652186521865216416524

dung ko??

\(=\frac{-\frac{1}{9}+1-\frac{2}{10}+1-\frac{3}{11}+1-...-\frac{92}{100}+1}{\frac{1}{9}+\frac{1}{10}+...+\frac{1}{100}}\)

\(=\frac{\frac{8}{9}+\frac{8}{10}+\frac{8}{11}+...+\frac{8}{100}}{\frac{1}{9}+\frac{1}{10}+...+\frac{1}{100}}\)

\(=\frac{8\left(\frac{1}{9}+\frac{1}{10}+\frac{1}{11}+...+\frac{1}{100}\right)}{\frac{1}{9}+\frac{1}{10}+\frac{1}{11}+...+\frac{1}{100}}\)

= 8

ta có: \(1-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}+\frac{19}{90}\)

\(=1-\frac{5}{2.3}+\frac{7}{3.4}-\frac{9}{4.5}+\frac{11}{5.6}-\frac{13}{6.7}+\frac{15}{7.8}-\frac{17}{8.9}+\frac{19}{9.10}\)

\(=1-\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{4}+\frac{1}{5}-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}-\frac{1}{8}+\frac{1}{9}-\frac{1}{9}+\frac{1}{10}\)

\(=1-\frac{1}{2}+\frac{1}{10}=\frac{3}{5}\)

quen mat cach lam rui hiiiiiii

\(1-\frac{5}{2.3}+\frac{7}{3.4}-\frac{9}{4.5}+\frac{11}{5.6}-\frac{13}{6.7}+\frac{15}{7.8}-\frac{17}{8.9}+\frac{19}{9.10}\)

tùy you giải z, t bt tek thui -_- 

lớp 5 này là dành cho h/s giỏi

\(B=\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+\frac{...89}{90}\)

\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)

\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)

\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)

\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=9-\left(1-\frac{1}{10}\right)\)

\(=9-\frac{9}{10}=8\frac{1}{10}\)