so sánh các phân số :
a) \(\frac{18}{91}v\text{à}\frac{23}{114}\) b) \(\frac{21}{52}v\text{à}\frac{213}{523}\) c) \(\frac{1313}{9191}v\text{à}\frac{1111}{7373}\)
so sánh
a)\(\frac{18}{91}\) và\(\frac{23}{114}\) b)\(\frac{21}{52}\) và\(\frac{213}{523}\) c)\(\frac{1313}{9191}\) và\(\frac{1111}{7373}\)
\(c\frac{1313}{9191}=\frac{1313:101}{9191:101}=\frac{13}{91}=\frac{1}{7}\)
\(\frac{1111}{7373}=\frac{1111:101}{7373:101}=\frac{11}{73}\)
\(mà\frac{1}{7}=\frac{1}{77}\Rightarrow\frac{11}{77}< \frac{11}{73}\)
vậy \(\frac{1313}{9191}< \frac{1111}{7373}\)
So sánh các phân số sau:
\(\frac{18}{91}\)và\(\frac{23}{114}\);\(\frac{21}{52}\)và\(\frac{213}{523}\);\(\frac{1313}{9191}\)và\(\frac{1111}{7373}\);\(\frac{n}{n+3}\)và\(\frac{n-1}{n+4}\);\(\frac{n}{2n+1}\)và\(\frac{3n+1}{6n+3}\)
SO SÁNH:
a)\(\frac{18}{91}\) và \(\frac{23}{114}\)
b)\(\frac{21}{52}\) và \(\frac{213}{523}\)
c)\(\frac{1313}{9191}\)và \(\frac{1111}{7373}\)
d)\(\frac{n}{n+1}\)và \(\frac{n+2}{n+3}\)
ai đúng mk tk~
a) Ta có :
\(\frac{18}{91}< \frac{18}{90}=\frac{1}{5}=\frac{23}{115}< \frac{23}{114}\)
\(\Rightarrow\frac{18}{91}< \frac{23}{114}\)
b) Ta có :
\(\frac{21}{52}=\frac{210}{520}=1-\frac{310}{520}\)
\(\frac{213}{523}=1-\frac{310}{523}\)
Mà \(1-\frac{310}{520}< 1-\frac{310}{523}\)
\(\Rightarrow\frac{21}{52}< \frac{213}{523}\)
c) Ta có : \(\frac{1313}{9191}=\frac{13}{91}=\frac{1}{7}=\frac{11}{77};\frac{1111}{7373}=\frac{11}{73}\)
Mà \(\frac{11}{77}< \frac{11}{73}\)nên \(\frac{1313}{9191}< \frac{1111}{7373}\)
d) Ta có :
\(\frac{n}{n+1}=\frac{n+1-1}{n+1}=1-\frac{1}{n+1}\)
\(\frac{n+2}{n+3}=\frac{n+3-1}{n+3}=1-\frac{1}{n+3}\)
Mà \(1-\frac{1}{n+1}< 1-\frac{1}{n+3}\)nên \(\frac{n}{n+1}< \frac{n+2}{n+3}\)
a) Ta có : \(\frac{18}{91}< \frac{18}{90}=\frac{1}{5}< \frac{23}{115}< \frac{23}{114}\)
\(\Rightarrow\) \(\frac{18}{91}< \frac{23}{114}\)
Vậy \(\frac{18}{91}< \frac{23}{114}\)
b) Ta có : \(\frac{21}{52}< \frac{21}{56}=\frac{3}{8}< \frac{213}{568}< \frac{213}{523}\)
\(\Rightarrow\) \(\frac{21}{52}< \frac{213}{523}\)
Vậy \(\frac{21}{52}< \frac{213}{523}\)
c) Ta có : \(\frac{1313}{9191}=\frac{1313:1313}{9191:1313}=\frac{1}{7}\)
\(\frac{1111}{7373}=\frac{1111:101}{7373:101}=\frac{11}{73}\)
Lại có : \(\frac{1}{7}< \frac{11}{77}< \frac{11}{73}\)
\(\Rightarrow\) \(\frac{1313}{9191}< \frac{1111}{7373}\)
Vậy \(\frac{1313}{9191}< \frac{1111}{7373}\)
d) Ta có : \(1-\frac{n}{n+1}=\frac{n+1}{n+1}-\frac{n}{n+1}=\frac{1}{n+1}\)
\(1-\frac{n+2}{n+3}=\frac{n+3}{n+3}-\frac{n+2}{n+3}=\frac{1}{n+3}\)
Vì \(n+1< n+3\)
\(\Rightarrow\)\(\frac{1}{n+1}>\frac{1}{n+3}\)
\(\Rightarrow\) \(\frac{n}{n+1}< \frac{n+2}{n+3}\)
Vậy \(\frac{n}{n+1}< \frac{n+2}{n+3}\)
Chúc m.n hok tốt ♡❤️
P/s :
a)
Ta có : \(\frac{18}{91}< \frac{18}{90}=\frac{1}{5}< \frac{23}{115}< \frac{23}{114}\)
\(\Rightarrow\) \(\frac{18}{91}< \frac{23}{114}\)
Vậy \(\frac{18}{91}< \frac{23}{114}\)
b)
Ta có : \(\frac{21}{52}< \frac{21}{56}=\frac{3}{8}< \frac{213}{568}< \frac{213}{523}\)
\(\Rightarrow\) \(\frac{21}{52}< \frac{213}{523}\)
Vậy \(\frac{21}{52}< \frac{213}{523}\)
c)
Ta có : \(\frac{1313}{9191}=\frac{1313:1313}{9191:1313}=\frac{1}{7}\)
\(\frac{1111}{7373}=\frac{1111:101}{7373:101}=\frac{11}{73}\)
Lại có : \(\frac{1}{7}< \frac{11}{77}< \frac{11}{73}\)
\(\Rightarrow\) \(\frac{1313}{9191}< \frac{1111}{7373}\)
Vậy \(\frac{1313}{9191}< \frac{1111}{7373}\)
d )
Ta có :
\(\frac{n}{n+1}=\frac{n+1-1}{n+1}=1-\frac{1}{n+1}\)
\(\frac{n+2}{n+3}=\frac{n+3-1}{n+3}=1-\frac{1}{n+3}\)
Do \(\frac{1}{n+1}>\frac{1}{n+3}\left(n+1< n+3\right)\)
\(\Rightarrow1-\frac{1}{n+1}>1-\frac{1}{n+3}\)
\(\Rightarrow\frac{n}{n+1}>\frac{n+2}{n+3}\)
Vậy ...
~ Ủng hộ nha
Không qui đồng, so sánh phân số sau:
a) \(\frac{18}{91}\)và \(\frac{23}{114}\)
b) \(\frac{1313}{9191}\)và \(\frac{1111}{7373}\)
a)\(\frac{18}{91}\)< \(\frac{23}{114}\) ; b) \(\frac{1313}{9191}\) < \(\frac{1111}{7373}\)
a)\(\frac{18}{91}\)\(< \)\(\frac{23}{114}\)
b)\(\frac{1313}{9191}\)\(< \)\(\frac{1111}{7373}\)
GIẢI CHI TIẾT GIÚP MÌNH NHA!
So sánh các phân số:
\(a.\frac{18}{91}và\frac{23}{114}\)
\(b.\frac{21}{52}và\frac{213}{523}\)
\(c.\frac{1313}{9191}và\frac{1111}{7373}\)
\(d.A=\frac{10^7+5}{10^7-8};B=\frac{10^8+6}{10^8-7}\)
\(e.A=\frac{10^{1992}+1}{10^{1991}+1};B=\frac{10^{1993}+1}{10^{1992}+1}\)
\(f.\frac{n}{n+3}và\frac{n-1}{n+4}\)
so sánh các phân số sau:
\(\frac{14}{19}v\text{à}\frac{21}{23}\)
\(\frac{14}{19}\)< \(\frac{21}{23}\)
Tích cho mình nha
So sánh các số hữu tỉ:
a) \(\frac{-17}{24}v\text{à}\frac{-25}{31}\)
b) \(\frac{-27}{38}v\text{à}\frac{-125}{195}\)
c) \(\frac{-22}{111}v\text{à}\frac{-27}{134}\)
a)-17/24 > -25/31
b)-27/38 < -125/195
c)-22/111> -27/134
nhớ k nha!!!!!!!!!!!!!!!!!!
So sánh các số hữu tỉ:
a) \(\frac{-17}{24}v\text{à}\frac{-25}{31}\)
b) \(\frac{-27}{38}v\text{à}\frac{-125}{195}\)
c) \(\frac{-22}{111}v\text{à}\frac{-27}{134}\)
* Giải chi tiết giúp mình !
a, \(\frac{-17}{24}< \frac{-25}{31}\)
b,\(\frac{-27}{38}< \frac{-125}{195}\)
c,\(\frac{-22}{111}>\frac{-27}{134}\)
So sánh :
a,\(\frac{7}{23}v\text{à}\frac{11}{28}\)
b,\(\frac{2014}{2015}+\frac{2015}{2016}v\text{à}\frac{2014+2015}{2015+2016}\)
c,A=\(\frac{2^{10}+1}{2^{11}+1}v\text{à B=\frac{2^{11}+1}{2^{12}+1}}\)
a)7/23<11/28
b)2014/2015+2015/2016>2014+2015/2015+2016
c) A= gì vậy