4-(7-x)=x-(13-4)

\(\Rightarrow4-7+x=x-13+4\)

\(\Rightarrow-3+x=x-17\)

\(\Rightarrow x\in\varnothing\)

Có thể sai để mình xem lại nha

bài 1 : -x+8=-17

=>-x=(-17)-8

=>x=-25

bài 2:-19-x=|-20|

=>x=20+(-19)

=>x=1

bài 3:35-x=-77

=>x=(-77)-35

=>x=-112

bài 4 :x-45=-17

=>x=(-17)+45

=>x=28

bài 5 : |x-3|=15

=>x-3=±5

TH1:x-3=5                         TH2:x-3=-5

=>x=8                                =>x=-2

bài 6:|x-3|-16=4

=>|x-3|=20

=>x-3=±20

TH1:x-3=20                      TH2:x-3=-20

=>x=23                            =>x=-17

bài 7:|x-7|+113=25

=>|x-7|=-88

=>x vô nghiệm

bài 8:26-|x+9|=-13

<=>26-|x+9|=-(|x+9|-26)

=>-(|x+9|-26=-13

=>x=-48 hoặc 30

bạn tự động não đi chứ đăng nhiều thế này mình làm mỏi hết cả tay

=>|x-9|=

hihi xin loi mk rui do

Có \(x+y=7+4\sqrt{3}+7-4\sqrt{3}=14\)

\(xy=\left(7-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)=1\)

\(x^2+y^2=\left(x+y\right)^2-2xy=14^2-2=194\)

\(x^3+y^3=\left(x+y\right)^3-3xy\left(x+y\right)=14^3-3.1.14=2702\)

\(x^7+y^7=\left(x^3+y^3\right)\left(x^4+y^4\right)-x^3y^3\left(x+y\right)\)\(=2702\left[\left(x^2+y^2\right)^2-2x^2y^2\right]-14\)

\(=2702\left(194^2-2\right)-14=101687054\)

Vậy...

\(x+y=14\) ; \(xy=\left(7+4\sqrt{3}\right)\left(7-4\sqrt{3}\right)=1\)

\(x^2+y^2=\left(x+y\right)^2-2xy=14^2-2.1=194\)

\(x^3+y^3=\left(x+y\right)^3-3xy\left(x+y\right)=14^3-3.1.14=2702\)

\(x^4+y^4=\left(x^2+y^2\right)^2-2\left(xy\right)^2=194^2-2.1^2=37634\)

\(x^7+y^7=\left(x^3+y^3\right)\left(x^4+y^4\right)-\left(xy\right)^3\left(x+y\right)=2702.37634-1^3.14=...\)

a)  \(\frac{3}{4}\times\frac{1}{2}\times2\)

C1: \(=\frac{3}{8}\times2=\frac{3}{4}\)

C2:  \(=\frac{3}{4}\times1=\frac{3}{4}\)

b)  \(\left[\frac{3}{4}+\frac{1}{2}\right]\times\frac{5}{7}\)

C1:  \(=\frac{5}{4}\times\frac{5}{7}=\frac{25}{28}\)

C2:   \(=\frac{3}{4}\times\frac{5}{7}+\frac{1}{2}\times\frac{5}{7}=\frac{15}{28}+\frac{5}{14}=\frac{25}{28}\)

a/\(\frac{3}{4}\cdot\frac{1}{2}\cdot2=\frac{6}{8}\cdot2=\frac{12}{8}=\frac{3}{2}\)

\(\frac{3}{4}\cdot\frac{1}{2}\cdot2=\frac{3}{4}\cdot\frac{2}{2}=\frac{3}{4}\cdot1=\frac{3}{4}\)

b/\(\left(\frac{3}{4}+\frac{1}{2}\right)\cdot\frac{5}{7}=\frac{5}{4}\cdot\frac{5}{7}=\frac{25}{28}\)

\(\left(\frac{3}{4}+\frac{1}{2}\right)\cdot\frac{5}{7}=\frac{3}{4}\cdot\frac{5}{7}+\frac{1}{2}\cdot\frac{5}{7}=\frac{15}{28}+\frac{5}{14}=\frac{15}{28}+\frac{10}{28}=\frac{25}{28}\)

c/\(\frac{5}{7}\cdot\frac{13}{21}+\frac{2}{7}\cdot\frac{13}{21}=\frac{65}{147}+\frac{26}{147}=\frac{91}{147}=\frac{13}{21}\)

\(\frac{5}{7}\cdot\frac{13}{21}+\frac{2}{7}\cdot\frac{13}{21}=\left(\frac{5}{7}+\frac{2}{7}\right)\cdot\frac{13}{21}=1\cdot\frac{13}{21}=\frac{13}{21}\)

Học tốt @#_#@

<br class="Apple-interchange-newline"><div id="inner-editor"></div>34 ·12 ·2=68 ·2=128 =32 

34 ·12 ·2=34 ·22 =34 ·1=34 

b/(34 +12 )·57 =54 ·57 =2528 

(34 +12 )·57 =34 ·57 +12 ·57 =1528 +514 =1528 +1028 =2528 

c/57 ·1321 +27 ·1321 =65147 +26147 =91147 =1321 

57 ·1321 +27 ·1321 =(57 +27 )·1321 =1·1321 =1321 

Học tốt @#_#@

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<br class="Apple-interchange-newline"><div id="inner-editor"></div>34 ·12 ·2=68 ·2=128 =32 

34 ·12 ·2=34 ·22 =34 ·1=34 

b/(34 +12 )·57 =54 ·57 =2528 

(34 +12 )·57 =34 ·57 +12 ·57 =1528 +514 =1528 +1028 =2528 

c/57 ·1321 +27 ·1321 =65147 +26147 =91147 =1321 

57 ·1321 +27 ·1321 =(57 +27 )·1321 =1·1321 =1321 

a) \(-39-\left(15+x\right)=18\)

\(-39-15-x=18\)

\(-54-x=18\)

\(x=-54-18\)

\(x=-72\)

vậy \(x=-72\)

b) \(31-\left(13+x\right)=18.\left(-4\right)\)

\(31-13-x=-72\)

\(18-x=-72\)

\(x=18+72\)

\(x=90\)

vậy \(x=90\)

c) \(58-\left(47+3x\right)=-18-2x\)

\(58-47-3x+2x=-18\)

\(11-x=-18\)

\(x=11+18\)

\(x=29\)

vậy \(x=29\)

d) \(37-\left(115+x\right)=188\)

\(37-115-x=188\)

\(-78-x=188\)

\(x=-78-188\)

\(x=-266\)

vậy \(x=-266\)

a)

\(-39-\left(15+x\right)=18\)

\(\Rightarrow15+x=-39-18\)

\(\Rightarrow15+x=-57\)

\(\Rightarrow x=-57-15\)

\(\Rightarrow x=-72\)

Vậy \(x=-72\)

b)

\(31-\left(13+x\right)=18.\left(-4\right)\)

\(\Rightarrow31-\left(13+x\right)=-72\)

\(\Rightarrow13+x=31-\left(-72\right)\)

\(\Rightarrow13+x=103\)

\(\Rightarrow x=103-13\)

\(\Rightarrow x=90\)

Vậy \(x=90\)

1. -x+20 = -(-15)-8+13

=> -x=15-8+13-20

=> -x=0

=> x=0

2. -(-10)+x=-13+(-9)+(-6)

=> 10+x=-13-9-6

=> x = -13-9-6-10

=> x = -38

3. 8-(-12)+10=-(-14)-x

=> 8+12+10=14-x

=> x = 14-8-12-10

=> x = -16

4. -(+12)+(-x)-(-3)=5-(-7)

=> -12-x+3=5+7

=> -x=5+7+12-3

=> -x=21

=> x=-21

5. 14-x+(-10)=-(-9)+(+15)

=> 14-x-10=9+15

=> -x=9+15-14+10

=> -x=20

=> x=-20

6. 12-(-17)+(-3)=-5+x

=> 12+17-3+5=x

=> x=31

7. x-(-19)-(+32)=14-(+16)

=> x+19-32=14-16

=> x=14-16+32-19

=> x=11

8. x-|-15|-|7|=-(-9)+|-5|

=> x-15-7=9+5

=> x=9+5+7+15

=> x=36

9. 15-x+17=13-(-21)

=> 15-x+17=13+21

=> -x=13+21-15-17

=> -x=2

=> x=-2

10. -|-5|-(-x)+4=3-(-25)

=> -5+x+4=3+25

=> x=3+25-4+5

=> x=29

a) \(2\left|x\right|-5=3\)

=> \(2\left|x\right|=3+5\)

=> \(2\left|x\right|=8\)

=> \(\left|x\right|=4\)

=> x = 4 hoặc x = -4

b) \(x-5=\left(-14\right)+2^3\)

=> \(x-5=\left(-14\right)+8\)

=> \(x-5=-6\)

=> \(x=-6+5=-1\)

c) \(10+2x=4^5:4^3\)

=> \(10+2x=4^{5-3}\)

=> \(10+2x=4^2\)

=> \(2x=4^2-10=16-10=6\)

=> \(2x=6\)

=> \(x=3\)

d) (x + 7) - 13 = 4

=> x + 7 = 17

=> x = 17 - 7 = 10

e) \(2x-10=2^4:2^2\)

=> \(2x-10=2^2\)

=> \(2x-10=4\)

=> \(2x=14\)

=> \(x=7\)

a) \(\frac{14}{15}:\frac{9}{10}=x:\frac{3}{7}\Rightarrow\frac{28}{27}=x:\frac{3}{7}\Rightarrow x=\frac{4}{9}\)

b) \(\left(x-\frac{4}{7}\right)^3=343\Rightarrow\left(x-\frac{4}{7}\right)^3=7^3\Rightarrow x-\frac{4}{7}=7\Rightarrow x=\frac{53}{7}\)

c) \(x^5=x^3\Leftrightarrow\hept{\begin{cases}x=1\\x=0\end{cases}}\)

e) \(\left(x-1\right)^4=16\Leftrightarrow\orbr{\begin{cases}\left(x-1\right)^4=2^4\\\left(x-1\right)^4=\left(-2\right)^4\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x-1=2\\x-1=\left(-2\right)\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)