Question

a) (x- 2)(x^2 +2x +4)

Answer 1

`(x-2)(x^2+2x+4)`

`=> x^3 +2x^2+4x-2x^2-4x-8`

`= >x^3 + (2x^2 - 2x^2)-(4x - 4x) - 8`

`=> x^3  - 8`

Answer 2

=x^3+2x^2+4x-2x^2-4x-8

=x^3-8

Answer 3

\(\left(x-2\right)\left(x^2+2x+4\right)\)

\(=4x^3+2x^2+4x-2x^2-4x-8\)

\(=x^3-8\)

Answer 4

(x - 2)(x² + 2x + 4)

= (x - 2)(x² + x.2 + 2²)

= x³ - 2³ = x³ - 8