Question

1. \(\dfrac{a-2\sqrt{a}}{2-\sqrt{a}}\) với a>= 0; a khác 4

2. \(\dfrac{1-a}{1+\sqrt{a}}\)

Answer 1

1. \(\dfrac{a-2\sqrt{a}}{2-\sqrt{a}}=\dfrac{\sqrt{a}\left(\sqrt{a}-2\right)}{2-\sqrt{a}}=\dfrac{-\sqrt{a}\left(2-\sqrt{a}\right)}{2-\sqrt{a}}=-\sqrt{a}\)

2. \(\dfrac{1-a}{1+\sqrt{a}}=\dfrac{\left(1-\sqrt{a}\right)\left(1+\sqrt{a}\right)}{1+\sqrt{a}}=1-\sqrt{a}\)

Answer 2

`a, =(sqrt a(sqrt a - 2))/(2 - sqrt a)`

`= -sqrt a`

`b, = ((1 + sqrt a)(1-sqrt a))/(1+sqrt a)`

`= 1 - sqrt a`.