a:Đặt A= \(\sqrt{36x^8\left(2-y\right)^2}\)

\(=\sqrt{36}\cdot\sqrt{x^8}\cdot\sqrt{\left(2-y\right)^2}\)

\(=6x^4\cdot\left|2-y\right|=6x^4\cdot\left|y-2\right|\)

mà y-2>=0(Do y>=2)

nên \(A=6x^4\left(y-2\right)=6x^4y-12x^4\)

b: \(\sqrt{\frac{7z}{3}}\cdot\sqrt{\frac{3}{28z}}=\sqrt{\frac{7z}{3}\cdot\frac{3}{28z}}=\sqrt{\frac{7}{28}}=\sqrt{\frac14}=\frac12\)

Lớp 3?

Dưới đây là kết quả rút gọn của các biểu thức: a) \(6x^{4}(y-2)\)b) \(\frac{z\sqrt{3}}{2}\) 1. Rút gọn biểu thức a Để rút gọn biểu thức \(\sqrt{36x^{8}(2-y)^{2}}\) với \(y\ge 2\), ta thực hiện các bước sau: Khai phương các thừa số: Sử dụng quy tắc \(\sqrt{A\cdot B\cdot C}=\sqrt{A}\cdot \sqrt{B}\cdot \sqrt{C}\) và \(\sqrt{A^{2}}=|A|\).\(\sqrt{36x^{8}(2-y)^{2}}=\sqrt{6^{2}}\cdot \sqrt{(x^{4})^{2}}\cdot \sqrt{(2-y)^{2}}\)\(=6\cdot |x^{4}|\cdot |2-y|\)Phá dấu giá trị tuyệt đối:Vì \(x^{4}\ge 0\) với mọi \(x\), nên \(|x^{4}|=x^{4}\).Vì \(y\ge 2\) nên \(2-y\le 0\). Do đó, \(|2-y|=-(2-y)=y-2\).Kết quả: \(6\cdot x^{4}\cdot (y-2)=6x^{4}(y-2)\). 2. Rút gọn biểu thức b Để rút gọn biểu thức \(\sqrt{7z^{3}}\cdot \sqrt{\frac{3}{28z}}\) với \(z>0\), ta thực hiện các bước sau: Nhân các căn thức: Sử dụng quy tắc \(\sqrt{A}\cdot \sqrt{B}=\sqrt{A\cdot B}\).\(\sqrt{7z^{3}\cdot \frac{3}{28z}}\)Rút gọn biểu thức trong căn:\(\sqrt{\frac{7\cdot 3\cdot z^{3}}{28\cdot z}}=\sqrt{\frac{21z^{2}}{28}}\)Rút gọn phân số \(\frac{21}{28}\) bằng cách chia cả tử và mẫu cho \(7\):\(\sqrt{\frac{3z^{2}}{4}}\)Khai phương kết quả:\(\frac{\sqrt{3}\cdot \sqrt{z^{2}}}{\sqrt{4}}=\frac{\sqrt{3}\cdot |z|}{2}\)Vì \(z>0\) nên \(|z|=z\). Ta được: \(\frac{z\sqrt{3}}{2}\). ✅ Kết quả Sau khi rút gọn, ta thu được:a) Biểu thức \(\sqrt{36x^{8}(2-y)^{2}}\) bằng \(6x^{4}(y-2)\).b) Biểu thức \(\sqrt{7z^{3}}\cdot \sqrt{\frac{3}{28z}}\) bằng \(\frac{z\sqrt{3}}{2}\). Bạn có cần hỗ trợ giải thêm các bài tập về trục căn thức ở mẫu hay các bài toán chứa tham số khác không?  Đang tạo đường liên kết công khai...Hữu íchKhông hữu íchCảm ơn bạnÝ kiến phản hồi của bạn sẽ giúp Google cải thiện. 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Em gõ lại đề cho dễ hiểu hí

đây là toán lớp 3 á!

Tuần sau đóng gop gấp `3` lần tuần đầu là :

`20xx3=60` (đồ dùng)

Tổng hai tuần là :

`60+20=80` (đồ dùng)

Đáp số : `80` đồ dùng

Số hộp bút chì mà thứ Chủ nhật bán được là :

`3xx12=36` (hộp)

Sau hai ngày bán của hàng đó bán được là :

`36+12=48` (hộp)

Đáp số : `48` hộp

Bài giải

Mỗi can đựng được 5 lít nước mắm.

Số can cần dùng để đựng 28 lít nước mắm là:

28 : 5 = 5 (dư 3)

Vì còn dư nước mắm nên cần thêm 1 can nữa.

Vậy cần ít nhất số can là:

5 + 1 = 6 (can)

Đáp số: 6 can

Chu vi HCN = 2(CD+CR) = 36, CD = 8 => CR = 36/2-8=10 cm

Cần thuê ít nhất số xe để chở số khách đó là:

50 : 7 = 7(dư 1)(xe)

Đáp số: 7(dư 1) làm tròn là 7 xe

rất hay vài ý nghĩa

Quá hay và thật ý nghĩa

hay cái gì mà hay,toán chứ đâu phải cái chổ để kể chuyện xàm

Nửa chu vi hình chữ nhật là: 68 : 2 = 34 (cm). Chiều rộng hình chữ nhật là: 34 - 23 = 11(cm). Đáp số: 11cm.

Nửa chu vi hình chữ nhật là 68:2=34(cm)

Chiều rộng hình chữ nhật là:

34-23=11(cm)

Nửa chu vi hình chữ nhật là 68:2=34(cm) Chiều rộng hình chữ nhật là: 34-23=11(cm)

đúng ko bạn

Thời gian trong khoảng từ 6h10p đến 6h40p là:

6h40p-6h10p=30p

30 phút

Thời gian trong khoảng từ 6h10p đến 6h40p là: 6h40p-6h10p=30p