Question

Tính: (3+1)(3²+1)(3⁴+1)(3⁸+1)(3¹⁶+1)(3³²+1)

Answer 1

đặt A=(3+1)(3²+1)(3⁴+1)(3⁸+1)(3¹⁶+1)(3³²+1)

=>2A=2.(3+1)(3²+1)(3⁴+1)(3⁸+1)(3¹⁶+1)(3³²+1)

=>2A=(3-1)(3+1)(3²+1)(3⁴+1)(3⁸+1)(3¹⁶+1)(3³²+1)

=(3²-1)(3²+1)(3⁴+1)(3⁸+1)(3¹⁶+1)(3³²+1)

=(3⁴-1)(3⁴+1)(3⁸+1)(3¹⁶+1)(3³²+1)

=(3⁸-1)(3⁸+1)(3¹⁶+1)(3³²+1)

=(3¹⁶-1)(3¹⁶+1)(3³²+1)

=(3³²-1)(3³²+1)

=3⁶⁴-1

=>2A=\(\frac{3^{64}-1}{2}\)

Answer 2

bạn ơi: A=\(\frac{3^{64}-1}{2}\) chứ ko phải 2A=\(\frac{3^{64}-1}{2}\)