(1𝑦/3+3)^3
(𝑦/3+3)^3
(𝑦/3+3⋅3/3)^3
(𝑦+3⋅3/3)^3
(𝑦+9/3)^3
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\(\left(\dfrac{1}{3}y+3\right)^3=\dfrac{1}{27}y^3+y^2+9y+27\)
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