\(ĐK:x\ge\dfrac{13}{3}\\ PT\Leftrightarrow2x-5=3x-13\\ \Leftrightarrow x=8\left(tm\right)\)
\(\sqrt{2x-5}=\sqrt{3x-13}\)
\(\Leftrightarrow3x-13=2x-5\)
hay x=8
\(\sqrt{2x-5}=\sqrt{3x-13}\left(ĐK:x\ge\dfrac{13}{3}\right)\)
<=> \(\left(\sqrt{2x-5}\right)^2=\left(\sqrt{3x-13}\right)^2\)
<=> \(\left|2x-5\right|=\left|3x-13\right|\)
<=> \(\left[{}\begin{matrix}2x-5=3x-13\\2x-5=-3x=13\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=8\left(tm\right)\\x=\dfrac{18}{5}\left(tm\right)\end{matrix}\right.\)
