Question

\(\sqrt{11-6\sqrt{2}}+3+\sqrt{2}\)

Answer 1

\(=3-\sqrt{2}+3+\sqrt{2}=6\)

Answer 2

\(\sqrt{11-6\sqrt{2}}+3+\sqrt{2}\\=\sqrt{9-2.3\sqrt{2}+2}+3+\sqrt{2}\\ =\sqrt{\left(3-\sqrt{2}\right)^2}+3+\sqrt{2}\\ =3-\sqrt{2}+3+\sqrt{2}\\ =6 \)