Question

Giúp mik với 

Answer 1

Answer 2

a, \(3x\left(x-y\right)-5x\left(y-x\right)=3x\left(x-y\right)+5x\left(x-y\right)\)

                                         \(=\left(3x+5x\right)\left(x-y\right)\)

                                          \(=8x\left(x-y\right)\)

Answer 3

b, \(9x^3\left(x-1\right)-9x^2\left(1-x\right)=9x^3\left(x-1\right)+9x^2\left(x-1\right)\)

                                              \(=\left(9x^3+9x^2\right)\left(x-1\right)\)

                                              \(=9x^2\left(x+1\right)\left(x-1\right)\)

Answer 4

c, \(x\left(x-y\right)^2-y\left(y-x\right)=x\left(x-y\right)\left(x-y\right)+y\left(x-y\right)\)

                                       \(=\left[x\left(x-y\right)+y\right]\left(x-y\right)\)

                                        \(=\left(x^2-xy+y\right)\left(x-y\right)\)

Answer 5

e,\(4x\left(x-2022\right)-x+2022=4x\left(x-2022\right)-\left(x-2022\right)\)

                                            \(=\left(4x-1\right)\left(x-2022\right)\)

Answer 6

\(a.3x\left(x-y\right)-5x\left(y-x\right)=3x\left(x-y\right)+5x\left(x-y\right)=\left(x-y\right)\left(3x+5x\right)=8x\left(x+y\right)\\ b.9x^3\left(x-1\right)-9x^2\left(1-x\right)=9x^3\left(x-1\right)+9x^2\left(x-1\right)=9x^2\left(x-1\right)\left(x+1\right)\\ c.x\left(x-y\right)^2-y\left(y-x\right)=x\left(x-y\right)^2+y\left(x-y\right)=\left(x-y\right)\left[x\left(x-y\right)+y\right]=\left(x-y\right)\left(x^2-xy+y\right)\\ d.2x\left(y-z\right)+\left(z-y\right)\left(z+t\right)=-2x\left(z-y\right)+\left(z-y\right)\left(z+t\right)=\left(z-y\right)\left(z+t-2x\right)\\ e.4x\left(x-2022\right)-x+2022=4x\left(x-2022\right)-\left(x-2022\right)=\left(4x-1\right)\left(x-2022\right)\)

Answer 7

a) \(3x\left(x-y\right)-5x\left(y-x\right)\)

\(=3x\left(x-y\right)+8x\left(x-y\right)\)

\(=11x\left(x-y\right)\)

b) \(9x^3\left(x-1\right)-9x^2\left(1-x\right)\)

\(=9x^3\left(x-1\right)+9x^2\left(x-1\right)\)

\(=9x^2\left(x-1\right)\cdot\left(x+1\right)\)

c) \(x\cdot\left(x-y\right)^2-y\left(y-x\right)\)

\(=x\left(x-y\right)^2+y\left(x-y\right)\)

\(=\left(x-y\right)\left[x\left(x-y\right)+y\right]\)

\(=\left(x-y\right)\left(x^2-xy+y\right)\)

Answer 8

d) \(2x\left(y-z\right)+\left(z-y\right)\left(z+t\right)\)

\(=2x\left(y-z\right)-\left(y-z\right)\left(z+t\right)\)

\(=\left(y-z\right)\left(2x-z-t\right)\)

e) \(4x\left(x-2022\right)-x+2022\)

\(=4x\left(x-2022\right)-\left(x-2022\right)\)

\(=\left(x-2022\right)\left(4x-1\right)\)

f) \(4\left(x-3y\right)^3\cdot\left(3x-y\right)^4-20\left(3y-x\right)\left(3x-y\right)^5\)

\(=4\left(x-3y\right)^3\cdot\left(3x-y\right)^4+20\left(x-3y\right)\cdot\left(3x-y\right)^5\)

\(=4\cdot\left(x-3y\right)\left(3x-y\right)^4\cdot\left[\left(x-3y\right)^2+5\cdot\left(3x-y\right)\right]\)