`(x-4)/5+(3x-2)/10-x=(2x-5)/3-(7x+2)/6`
`<=>(2(x-4))/10+(3x-2)/10-(10x)/10=(2(2x-5))/6-(7x+2)/6`
`<=>(2x-8+3x-2-10x)/10=(4x-10-7x-2)/6`
`<=>(-5x-10)/10=(-3x-12)/6`
`<=>(-5(x+2))/10=(-3(x+4))/6`
`<=>(x+2)/-2=(x+4)/-2`
`<=>x+2=x+4`
`<=>2=4`
Điều này vô lý
=> Không có x thỏa mãn
\(...\Leftrightarrow\dfrac{12\left(x-4\right)+6\left(3x-2\right)-60x}{60}=\dfrac{20\left(2x-5\right)-10\left(7x+2\right)}{60}\)
\(\Leftrightarrow12x-48+18x-12-60x=40x-100-70x-20\)
\(\Leftrightarrow0x=60\left(vô.lý\right)\)
\(\Leftrightarrow x\in\varnothing\)
\(30 . ( \dfrac{x-4}{5}) + 30 . (\dfrac{3x-2}{10}) - 30x = 30 . ( \dfrac{2x-5}{3}) - 30 . (\dfrac{7x+2}{6})\)
` 6(x-40 + 3(3x - 2) - 30x = 10(2x-5)-5(7x+2) `
` 6x - 24 + 9x - 6 - 30x = 20x - 50 - 35x - 10 `
` ( 6x + 9x - 30x) - (-24 - 6) = ( 20x - 35x) - ( -50 - 10) `
` -15x - 30 = -15x - 60 `
` -15x + 15 x = -60 + 30 `
` => 0 = -30 `
`=> ` Không có x thỏa mãn
