Question

Bài 1:

a)So sánh \(\left(\dfrac{3}{4}\right)^{2021}+1với\dfrac{3}{4}+1\)

b)Cho x,y,z khác 0 thỏa mãn

\(\dfrac{2x-3}{5}=\dfrac{5y-2z}{3}=\dfrac{3z-5x}{2}\)

Tính GTBT: B=\(\dfrac{12x-5y-3z}{x-3y+2z}\)

Answer 1

help me ai nhanh nhất mik tích cho

Answer 2

a) Ta có: \(\left(\dfrac{3}{4}\right)^{2021}>\left(\dfrac{3}{4}\right)^1=\dfrac{3}{4}\)

\(\Leftrightarrow\left(\dfrac{3}{4}\right)^{2021}+1>\dfrac{3}{4}+1\)