\(4x^2-4x-3=0\\ \Leftrightarrow\left(4x^2-4x+1\right)-4=0\\ \Leftrightarrow\left(2x-1\right)^2-2^2=0\\ \Leftrightarrow\left(2x-1-2\right)\left(2x-1+2\right)=0\\ \Leftrightarrow\left(2x-3\right)\left(2x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{-1}{2}\end{matrix}\right.\)
Vậy \(x\in\left\{\dfrac{3}{2};-\dfrac{1}{2}\right\}\) là nghiệm của pt.
\(4x^2-4x-3=0\)
\(\Leftrightarrow\left(2x-1\right)^2-4=0\)
\(\Leftrightarrow\left(2x-1-2\right)\left(2x-1+2\right)=0\)
\(\Leftrightarrow\left(2x-3\right)\left(2x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\2x+1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)
Ta có: \(4x^2-4x-3=0\)
\(\Leftrightarrow\left(2x-3\right)\left(2x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)
