Question

16x2-8x+1

Answer 1

\(16x^2-8x+1\\ =\left(16x^2-4x\right)-\left(4x-1\right)\\ =4x\left(4x-1\right)-\left(4x-1\right)\\ =\left(4x-1\right)\left(4x-1\right)\\ =\left(4x-1\right)^2\)

Answer 2

 (4x)^2 - 2.4x.1 + 1 = 0

 (4x - 1)^2 = 0

4x - 1 = 0

x = 1/4

Answer 3

\(16x^2-8x+1=\left(4x-1\right)^2\)