\(tana=3=>cota=\dfrac{1}{tana}=\dfrac{1}{3}\)
\(1+tan^2a=\dfrac{1}{cos^2a}\\ =>cos^2a=\dfrac{1}{1+tan^2a}=\dfrac{1}{1+3^2}=\dfrac{1}{10}\\=>cosa=\sqrt{\dfrac{1}{10}}=\dfrac{\sqrt{10}}{10}\\ sin^2a+cos^2a=1\\ =>sina=\sqrt{1-cos^2a}=\sqrt{1-\left(\dfrac{\sqrt{10}}{10}\right)^2}=\dfrac{3\sqrt{10}}{10}\)