Trong số các hoạt động ngoại khóa mà em đã tham gia, buổi lao động trồng cây tại sân trường để lại ấn tượng sâu sắc nhất trong lòng em. Vào ngày hôm đó, thầy cô đã hướng dẫn cả lớp trồng những cây hoa mới dọc theo lối đi. Dù thời tiết nắng nóng, mọi người vẫn tỏ ra phấn khởi và trò chuyện vui vẻ. Em cùng các bạn hăng hái bắt tay vào việc đào đất, đặt cây con vào vị trí và nhẹ nhàng lấp đất lại. Khi em tưới những gáo nước đầu tiên cho cây, em cảm thấy rất hạnh phúc và tự hào vì đã góp phần vào việc bảo vệ môi trường cũng như cho ngôi trường thân yêu của mình. Sau ngày hôm đó, mỗi khi đi qua hàng cây nhỏ đang lớn lên từng ngày, em lại nhớ về khoảnh khắc cả lớp cùng nhau làm việc, đoàn kết và tràn đầy sức sống. Hoạt động này không chỉ giúp em nhận thức rõ hơn về tầm quan trọng của việc bảo vệ môi trường, mà còn mang lại cho em một kỷ niệm đẹp không thể nào quên.

A:>

đáp án (thêm) C tất cả.

tất nhiên là a

hi

Bạn nhấn vào nút "Tham gia nhóm Học sinh Hoc24OLM" ngay phía trên để tham gia lớp và truy cập phần lý thuyết. Sau khi tham gia, bạn chọn thẻ Lý thuyết để xem nội dung. Nếu trang bị lỗi, bạn thử tải lại trang hoặc liên hệ hỗ trợ.

trên bàn cờ vua

trên bàn cờ vua.

trên bàn cờ vua

a:Đặt A= \(\sqrt{36x^8\left(2-y\right)^2}\)

\(=\sqrt{36}\cdot\sqrt{x^8}\cdot\sqrt{\left(2-y\right)^2}\)

\(=6x^4\cdot\left|2-y\right|=6x^4\cdot\left|y-2\right|\)

mà y-2>=0(Do y>=2)

nên \(A=6x^4\left(y-2\right)=6x^4y-12x^4\)

b: \(\sqrt{\frac{7z}{3}}\cdot\sqrt{\frac{3}{28z}}=\sqrt{\frac{7z}{3}\cdot\frac{3}{28z}}=\sqrt{\frac{7}{28}}=\sqrt{\frac14}=\frac12\)

Lớp 3?

Dưới đây là kết quả rút gọn của các biểu thức: a) \(6x^{4}(y-2)\)b) \(\frac{z\sqrt{3}}{2}\) 1. Rút gọn biểu thức a Để rút gọn biểu thức \(\sqrt{36x^{8}(2-y)^{2}}\) với \(y\ge 2\), ta thực hiện các bước sau: Khai phương các thừa số: Sử dụng quy tắc \(\sqrt{A\cdot B\cdot C}=\sqrt{A}\cdot \sqrt{B}\cdot \sqrt{C}\) và \(\sqrt{A^{2}}=|A|\).\(\sqrt{36x^{8}(2-y)^{2}}=\sqrt{6^{2}}\cdot \sqrt{(x^{4})^{2}}\cdot \sqrt{(2-y)^{2}}\)\(=6\cdot |x^{4}|\cdot |2-y|\)Phá dấu giá trị tuyệt đối:Vì \(x^{4}\ge 0\) với mọi \(x\), nên \(|x^{4}|=x^{4}\).Vì \(y\ge 2\) nên \(2-y\le 0\). Do đó, \(|2-y|=-(2-y)=y-2\).Kết quả: \(6\cdot x^{4}\cdot (y-2)=6x^{4}(y-2)\). 2. Rút gọn biểu thức b Để rút gọn biểu thức \(\sqrt{7z^{3}}\cdot \sqrt{\frac{3}{28z}}\) với \(z>0\), ta thực hiện các bước sau: Nhân các căn thức: Sử dụng quy tắc \(\sqrt{A}\cdot \sqrt{B}=\sqrt{A\cdot B}\).\(\sqrt{7z^{3}\cdot \frac{3}{28z}}\)Rút gọn biểu thức trong căn:\(\sqrt{\frac{7\cdot 3\cdot z^{3}}{28\cdot z}}=\sqrt{\frac{21z^{2}}{28}}\)Rút gọn phân số \(\frac{21}{28}\) bằng cách chia cả tử và mẫu cho \(7\):\(\sqrt{\frac{3z^{2}}{4}}\)Khai phương kết quả:\(\frac{\sqrt{3}\cdot \sqrt{z^{2}}}{\sqrt{4}}=\frac{\sqrt{3}\cdot |z|}{2}\)Vì \(z>0\) nên \(|z|=z\). Ta được: \(\frac{z\sqrt{3}}{2}\). ✅ Kết quả Sau khi rút gọn, ta thu được:a) Biểu thức \(\sqrt{36x^{8}(2-y)^{2}}\) bằng \(6x^{4}(y-2)\).b) Biểu thức \(\sqrt{7z^{3}}\cdot \sqrt{\frac{3}{28z}}\) bằng \(\frac{z\sqrt{3}}{2}\). Bạn có cần hỗ trợ giải thêm các bài tập về trục căn thức ở mẫu hay các bài toán chứa tham số khác không?  Đang tạo đường liên kết công khai...Hữu íchKhông hữu íchCảm ơn bạnÝ kiến phản hồi của bạn sẽ giúp Google cải thiện. 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Em gõ lại đề cho dễ hiểu hí

đây là toán lớp 3 á!

Tuần sau đóng gop gấp `3` lần tuần đầu là :

`20xx3=60` (đồ dùng)

Tổng hai tuần là :

`60+20=80` (đồ dùng)

Đáp số : `80` đồ dùng