\(x\left(2x-3\right)-\left(4x^2-9\right)=0\\ \Rightarrow x\left(2x-3\right)-\left(2x-3\right)\left(2x+3\right)=0\\ \Rightarrow\left(2x-3\right)\left(x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-3\end{matrix}\right.\)
\(\Leftrightarrow\left(2x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-3\end{matrix}\right.\)
x(2x-3)-(4x2-9)=0
x(2x-3)-[(2x)2-32 ] = 0
x(2x-3)-(2x-3)(2x+3)=0
(2x-3)x(2x+3)=0
Khi và chỉ khi:
x= 0 hoặc 2x-3=0 hoặc 2x+3= 0
2x=3 hoặc 2x= -3
x=3/2 hoặc x= -3/2
Vậy x= 0; x= 3/2; x=-3/2
