\(\sqrt{\dfrac{-2x}{x^2+1}}\)
Có nghĩa khi:
\(\left\{{}\begin{matrix}\dfrac{-2x}{x^2+1}\ge0\\x^2+1\ne0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}-2x\ge0\\x^2\ne-1\left(\text{luôn đúng}\right)\end{matrix}\right.\)
\(\Leftrightarrow x\le0\)