\(\sqrt{\dfrac{1}{-1+x}}=\sqrt{\dfrac{1}{x-1}}\) có nghĩa khi:
\(\left\{{}\begin{matrix}\dfrac{1}{x-1}\ge0\\x-1\ne0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-1\ge0\\x\ne1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\ge1\\x\ne1\end{matrix}\right.\)
\(\Leftrightarrow x>1\)
\(ĐKXĐ:\dfrac{1}{-1+1x}>0\Leftrightarrow-1+1x< 0\\ \Leftrightarrow x< -1\)