Ta có: \(n_{CuSO_4}=\dfrac{16}{160}=0,1\left(mol\right)\)
\(\Rightarrow C_{M_{CuSO_4}}=\dfrac{0,1}{0,1}=1M\)
Bạn tham khảo nhé!
nCuSO4=
100ml =0,1 lít
\(n_{CuSO_4}\) =16 :(64 +32+16.4)= 0,1 mol
=>Cm =\(\dfrac{0,1}{0,1}\) =1 M (Cm =\(\dfrac{n}{V_{dd}}\) )
n\(_{CuSO_4}\) = \(\dfrac{16}{160}=0,1\left(mol\right)\)
\(C_{M_{CuSO_4}}\) = \(\dfrac{0,1}{0,1}=0,01\left(M\right)\)