Question

Tính số mol :

a. 150g dung dịch HCl 12%

b. 50g dung dịch H₂SO₄ 10%

c. 100g dung dịch AgNO₃ 12% 

Answer 1

\(a.m_{HCl}=\dfrac{150.12}{100}=18\left(g\right)\\ n_{HCl}=\dfrac{18}{36,5}\approx0,5\left(mol\right)\\ b.m_{H_2SO_4}=\dfrac{50.10}{100}=5\left(g\right)\\ n_{H_2SO_4}=\dfrac{5}{98}\approx0,05\left(mol\right)\\ c.m_{AgNO_3}=\dfrac{100.12}{100}=12\left(g\right)\\ n_{AgNO_2}=\dfrac{12}{170}\approx0,07\left(mol\right)\)

Answer 2

a.

\(m_{HCl}=\dfrac{150.12\%}{100\%}=18\left(g\right)\\ \Rightarrow n_{HCl}=\dfrac{18}{36,5}\approx0,5\left(mol\right)\)

b. 

\(m_{H_2SO_4}=\dfrac{50.10\%}{100\%}=5\left(g\right)\\ \Rightarrow n_{H_2SO_4}=\dfrac{5}{98}\approx0,05\left(mol\right)\)

c. 

\(m_{AgNO_3}=\dfrac{100.12\%}{100\%}=12\left(g\right)\\ \Rightarrow n_{AgNO_3}=\dfrac{12}{170}\approx0,07\left(mol\right)\)