Question

Tính các đa thức sau:

a) 36²+26²-52*36

b) 2004²-16²

Answer 1

a, \(36^2+26^2-52.36=36^2-2.26.36+26^2=\left(36-26\right)^2=10^2=100\)

\(b,2004^2-16^2=\left(2004-16\right)\left(2004+16\right)=1988.2020=4015760\)

Answer 2

\(a,36^2+26^2-52.36\)

\(=36^2-2.26.36+26^2\)

\(=\left(36-26\right)^2\)

\(=10^2=100\)

\(b,2004^2-16^2\)

\(=\left(2004-16\right)\left(2004+16\right)\)

\(=1988.2020\)

\(=4015760\)