a/ x(x-2)-y(2-x)=0
<=>x(x-2)+y(x-2)=0
<=>(x+y)(x-2)=0
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x+y=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-y\end{cases}}\)
b/ 2x2-4x=0
<=>2x(x-2)=0
\(\Leftrightarrow\orbr{\begin{cases}2x=0\\x-2=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)
nho -ick minh nhe
Tìm x:
a) 5x(x-2)+(2-x)=0
b) x(2x-5)-10x+25=0
c) \(\dfrac{25}{16}\)-4x2+4x-1=0
d)x4+2x2-8=0
Tìm x:
a) x4-25x3=0
b) (x-5)2-(3x-2)2=0
c) x3-4x2-9x+36=0
d) (-x3+3x2-4x) : (\(-\dfrac{1}{2}\)x)=0
Tìm x:
a) 36x3-4x=0
b) 3x(x-2)-2+x=0
c) (x3-x2)-4x2+8x-4=0
d) x2-6x-16=0
e) x4-6x2-7=0
Tìm x:
a) 36x3-4x=0
b) 3x(x-2)-2+x=0
c) (x3-x2)-4x2+8x-4=0
d) x2-6x-16=0
e) x4-6x2-7=0
(Mình cần gấp ạ)
Tìm x:
a)(x+3)2-4x-12=0
b)x(x+5)(x-5)-(x-3)(x2+3x+9)=7
1) Phân tích đa thức thành nhân tử
a) 2x4-4x3+2x2
b) 2x2-2xy+5x-5y
2) Tìm x, biết:
a) 4x(x-3)-x+3=0
b)(2x-3)2-(x+1)2=0
Tìm x:
a)x.(x+7)-(x-2).(x+3)=0
b)(x+2)2-(x2-4)=0
Tìm x:
a, x(2x – 3) – 2(3 – 2x) = 0
b, (x – 3)(x2 + 3x + 9) – x(x + 2)(x – 2) = 1
c, 4x2 + 4x – 6 = 2
d, 2x2 + 7x + 3 = 0
Tìm x:
a) 3x2+ 6x = 0
b)x (x − 1) + 2x − 2 = 0
Tìm x:
a)5x(x-2)-2x+4=0
b)2x(x+1)-(x-2)^2=6
c)2x^2+7x-9=0
