a: Ta có: \(\left(x-3\right)\left(x^2+3x+9\right)-x\left(x^2-3\right)=0\)
\(\Leftrightarrow x^3-27-x^3+3x=0\)
\(\Leftrightarrow x=9\)
b: Ta có: \(8x^4+x=0\)
\(\Leftrightarrow x\left(8x^3+1\right)=0\)
\(\Leftrightarrow x\left(2x+1\right)\left(4x^2-2x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{2}\end{matrix}\right.\)
Tìm x:
a) 36x3-4x=0
b) 3x(x-2)-2+x=0
c) (x3-x2)-4x2+8x-4=0
d) x2-6x-16=0
e) x4-6x2-7=0
Tìm x:
a) 36x3-4x=0
b) 3x(x-2)-2+x=0
c) (x3-x2)-4x2+8x-4=0
d) x2-6x-16=0
e) x4-6x2-7=0
(Mình cần gấp ạ)
Tìm x:
a) (3x-2)(2x-1)-(6x2-3x)=0
b) x3-(x+1)(x2-x+1)=x
c) 56x4+7x=0
d) x2-5x-24=0
Tìm x:
a) x(x-2)-x+2=0
b) (3-2x)2-(x-1)2=0
c) 81x4-x2=0
d) x3+x2+27x+27=0
Tìm x:
a) x(x-2)-x+2=0
b) (3-2x)2-(x-1)2=0
c) 81x4-x2=0
d) x3+x2+27x+27=0
.Tìm x biết:
a) 3x(x – 2) – x + 2 = 0
b) x3 – 6x2 + 12x – 8 = 0
c) 16x2 – 9(x + 1)2
d) x2 (x – 1) – 4x2 + 8x – 4 = 0
Tìm x:
a) 64x5-4x3=0
b) x3-81x=0
c) x(5-3x)-5+3x=0
d) 4x3+12x2-9x-27=0
e) x4-6x2+7=0
Tìm x:
a) 64x5-4x3=0
b) x3-81x=0
c) x(5-3x)-5+3x=0
d) 4x3+12x2-9x-27=0
e) x4-6x2+7=0
Tìm x:
a) x2+9x=0
b) (x+4)2-16=0
c) x3-16x=0
d) x2-10x+25=0
