Question

tìm x: (x-1,5)^6+2(1,5-x)^2 = 0
Kiến thức phân tích đa thức thành nhân tử nha mn

Answer 1

\(\left(x-1,5\right)^6+2.\left(1,5-x\right)^2=0\\ \Leftrightarrow\left(x-1,5\right)^6+2.\left(x-1,5\right)^2=0\\ \Leftrightarrow\left(x-1,5\right)^2.\left[\left(x-1,5\right)^4+2\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-1,5\right)^2=0\\\left(x-1,5\right)^4+2\ge0\forall x\in R\end{matrix}\right.\\ \Leftrightarrow x=1,5\)

Vậy x=1,5

Answer 2

Ta có: \(\left(x-1.5\right)^6+2\left(1.5-x\right)^2=0\)

\(\Leftrightarrow x-1.5=0\)

hay x=1,5