Question

TÌM X biết:

\(\dfrac{3x}{6x+3}=\dfrac{x}{2x+2}\)

Answer 1

3x/6x+3=x/2x+2

⇒6x²+6x=6x²+3x

⇒ 6x²+6x-6x²-3x=0

⇒ 3x=0

⇒ x=0

Answer 2

`(3x)/(6x+3)=x(2x+2)`      ĐKXĐ : `x \ne -1/2 ; x \ne -1`

`->3x(2x+2)=x(6x+3)`

`->6x^2+6x=6x^2+3x`

`->3x=0`

`->x=0` ( tm )

Vậy `x=0`

Answer 3

Ta có: \(\dfrac{3x}{6x+3}=\dfrac{x}{2x+2}\)

\(\Leftrightarrow3x\left(2x+2\right)=x\left(6x+3\right)\)

\(\Leftrightarrow6x^2+6x-6x^2-3x=0\)

\(\Leftrightarrow3x=0\)

hay x=0