Question

tìm x : 1/3 . x - 1/6 = 1/9 . x - 1/12 

Answer 1

\(\dfrac{1}{3}\cdot x-\dfrac{1}{6}=\dfrac{1}{9}\cdot x-\dfrac{1}{12}\\ \dfrac{1}{3}\cdot x-\dfrac{1}{9}\cdot x=\dfrac{1}{6}-\dfrac{1}{12}\\ x\cdot\left(\dfrac{1}{3}-\dfrac{1}{9}\right)=\dfrac{1}{6}-\dfrac{1}{12}\\ x\cdot\dfrac{2}{9}=\dfrac{1}{12}\\ x=\dfrac{1}{12}:\dfrac{2}{9}=\dfrac{1}{12}\cdot\dfrac{9}{2}\\ x=\dfrac{3}{8}\)

Answer 2

\(\dfrac{1}{3}\cdot x-\dfrac{1}{6}=\dfrac{1}{9}\cdot x-\dfrac{1}{12}\)

\(\dfrac{1}{9}\cdot x-\dfrac{1}{3}\cdot x=-\dfrac{1}{6}+\dfrac{1}{12}\)

\(-\dfrac{2}{9}\cdot x=-\dfrac{2}{12}+\dfrac{1}{12}\)

\(-\dfrac{2}{9}\cdot x=-\dfrac{1}{12}\)

\(x=-\dfrac{1}{12}:\dfrac{-2}{9}\)

\(x=\dfrac{3}{8}\)

Answer 3

sai r cái kia là nhân không phải trừ 

Answer 4

Cụ thể là sai chỗ nào em nhỉ?