\(\dfrac{1}{3}\cdot x-\dfrac{1}{6}=\dfrac{1}{9}\cdot x-\dfrac{1}{12}\\ \dfrac{1}{3}\cdot x-\dfrac{1}{9}\cdot x=\dfrac{1}{6}-\dfrac{1}{12}\\ x\cdot\left(\dfrac{1}{3}-\dfrac{1}{9}\right)=\dfrac{1}{6}-\dfrac{1}{12}\\ x\cdot\dfrac{2}{9}=\dfrac{1}{12}\\ x=\dfrac{1}{12}:\dfrac{2}{9}=\dfrac{1}{12}\cdot\dfrac{9}{2}\\ x=\dfrac{3}{8}\)
\(\dfrac{1}{3}\cdot x-\dfrac{1}{6}=\dfrac{1}{9}\cdot x-\dfrac{1}{12}\)
\(\dfrac{1}{9}\cdot x-\dfrac{1}{3}\cdot x=-\dfrac{1}{6}+\dfrac{1}{12}\)
\(-\dfrac{2}{9}\cdot x=-\dfrac{2}{12}+\dfrac{1}{12}\)
\(-\dfrac{2}{9}\cdot x=-\dfrac{1}{12}\)
\(x=-\dfrac{1}{12}:\dfrac{-2}{9}\)
\(x=\dfrac{3}{8}\)
Cụ thể là sai chỗ nào em nhỉ?
Z biết: 1) x + 35 = 8 ; 2) 15 – ( 4 – x) = 6 ; 
Z thì: M = a(a + 3) – a(a – 5) – 8 là bội của 8. 
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