Question

thực hiện phép tính

\(10.(2√3-3√2)^2+2√6+3√24\)

Answer 1

\(=12+18-3\cdot2\sqrt{3}\cdot3\sqrt{2}+2\sqrt{6}+6\sqrt{6}\)

\(=30-18\sqrt{6}+8\sqrt{6}=30-10\sqrt{6}\)

Answer 2

*Lời giải chi tiết:
\(10\left(2\sqrt{3}-3\sqrt{2}\right)^2+2\sqrt{6}+3\sqrt{24}\)
=\(10\left(12-12\sqrt{6}+18\right)+2\sqrt{6}+6\sqrt{6}\)
=\(120-120\sqrt{6}+180+2\sqrt{6}+6\sqrt{6}\)
=\(300-112\sqrt{6}\)