ĐKXĐ: \(m\ne0\)
\(\dfrac{2m+1}{m}< =0\)
TH1: \(\left\{{}\begin{matrix}2m+1< =0\\m>0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}m< =-\dfrac{1}{2}\\m>0\end{matrix}\right.\)
=>\(m\in\varnothing\)
TH2: \(\left\{{}\begin{matrix}2m+1>=0\\m< 0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}m>=-\dfrac{1}{2}\\m< 0\end{matrix}\right.\)
=>\(-\dfrac{1}{2}< =m< 0\)