Ta có: \(\sqrt{2-\sqrt{3}}-\sqrt{2+\sqrt{3}}\)
\(=\dfrac{\sqrt{4-2\sqrt{3}}-\sqrt{4+2\sqrt{3}}}{\sqrt{2}}\)
\(=\dfrac{\sqrt{3}-1-\sqrt{3}-1}{\sqrt{2}}=-\sqrt{2}\)
rút gọn M=\(\dfrac{\sqrt{\sqrt{7}-\sqrt{3}}-\sqrt{\sqrt{7}+\sqrt{3}}}{\sqrt{7}-2}\)
Rút gọn
\(\frac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2}+\sqrt{3}}+\frac{2-\sqrt{3}}{\sqrt{2}+\sqrt{2}-\sqrt{3}}\)
Rút gọn biểu thức
\(\sqrt{\frac{2+\sqrt{3}}{2}}-\sqrt{\frac{2-\sqrt{3}}{2}}\)
Rút gọn 1 / sqrt (2) - sqrt (3) -sqrt(3)-sqrt(5)+1/sqrt(5)-sqrt(7)
Rút gọn :\(A=\frac{\sqrt{6+2.\left(\sqrt{6}+\sqrt{3}+\sqrt{2}\right)}-\sqrt{6-2.\left(\sqrt{6}-\sqrt{3}-\sqrt{2}\right)}}{\sqrt{2}}\)
Rút gọn biểu thức sau
a)\(\sqrt{3-\sqrt{5}}\left(\sqrt{10}-\sqrt{2}\right)\left(3+\sqrt{5}\right)\)
b)\(\sqrt{2+\sqrt{3}}\sqrt{2+\sqrt{2+\sqrt{3}}.\sqrt{2}}-\sqrt{2+\sqrt{2}}\)
Rút gọn
\(\frac{\sqrt{160}-\sqrt{80}}{\sqrt{8}-\sqrt{2}}-\frac{\sqrt{40}-\sqrt{15}}{2\sqrt{2}-\sqrt{3}}\)
Rút gọn :
\(B=\sqrt{3+\sqrt{5}}-\sqrt{3\sqrt{5}}-\sqrt{2}\)
Rút gọn A=\(\frac{\sqrt{2-\sqrt{3}}.\left(4+3.\sqrt{2}\right)}{\sqrt{3}-1}\)
