Question

Rút gọn các biểu thức: x^2+4/x^2+2x+4/x+2, với x ko=0; x ko=-2

Answer 1

\(=\dfrac{x^2+4}{x\left(x+2\right)}+\dfrac{4}{x+2}=\dfrac{x^2+4x+4}{x\left(x+2\right)}=\dfrac{x+2}{x}\)

Answer 2

\(\dfrac{x^2+4}{x^2+2x}+\dfrac{4}{x+2}=\dfrac{x^2+4+4x}{x\left(x+2\right)}=\dfrac{\left(x+2\right)^2}{x\left(x+2\right)}=\dfrac{x+2}{x}\)