Question

Phân tích thành nhân tử

(3x+2)^2-(x-6)^2

Answer 1

(3x+2)²-(x-6)²=(3x+2-x+6)(3x+2+x-6)=(2x+8)(4x-4)=8(x+4)(x-1)

Answer 2

\((3x+2)^2-(x-6)^2=(3x+2-x+6)(3x+2+x-6) =(2x+8)(4x-4)=2.4(x+4)(x-1)=8(x+4)(x-1)\)

Answer 3

\(\left(3x+2\right)^2-\left(x-6\right)^2\)

\(=\left(3x+2+x-6\right)\left(3x+2-x+6\right)\)

\(=\left(4x-4\right)\left(2x+8\right)\)

\(=8\left(x-1\right)\left(x+4\right)\)