Question

Phân tích thành nhân tử

(3x+2)^2-(x-6)^2=0

Answer 1

\(\left(3x+2\right)^2-\left(x-6\right)^2=\left(3x+2-x+6\right)\left(3x+2+x-6\right)=\left(2x+8\right)\left(4x-4\right)=8\left(x+4\right)\left(x-1\right)\)

Answer 2

\(\left(3x+2\right)^2-\left(x-6\right)^2\)

\(=\left(3x+2+x-6\right)\left(3x+2-x+6\right)\)

\(=\left(4x-4\right)\left(2x+8\right)\)

\(=8\left(x-1\right)\left(x+4\right)\)