Question

Phân tích đa thức sau thành nhân tử

8+8\(\left(x-2\right)^3\)

Answer 1

\(8+8\left(x-2\right)^3\)

\(=8\left[1+\left(x-2\right)^3\right]\)

\(=8\left(1+x-2\right)\left[1-\left(x-2\right)+\left(x-2\right)^2\right]\)

\(=8\left(x-1\right)\left(1-x+2+x^2-4x+4\right)\)

\(=8\left(x-1\right)\left(x^2-5x+7\right)\)

#\(Toru\)

Answer 2

=8[(x-2)^3+1]

=8(x-2+1)[(x-2)^2-(x-2)+1]

=8(x-1)(x^2-4x+4-x+2+1)

=8(x-1)(x^2-5x+7)

Answer 3

8 + 8(x - 2)³

= 8[1 + (x - 2)³]

= 8(1 + x - 2)[1 - x + 2 + (x - 2)²]

= 8(x - 1)(3 - x + x² - 4x + 4)

= 8(x - 1)(x² - 5x + 7)