Question

Phân tích các đa thức sau thành nhân tử:
a) 6x³y-9x²y²+3xy
b) x²-3x+xy-3y
c) x²-y²-4x+4

Answer 1

b) x²-3x+xy-3y

=\(\left(x^2+xy\right)-\left(3x+3y\right)\)

=\(x\left(x+y\right)-3\left(x+y\right)\)

=\(\left(x-3\right)\left(x+y\right)\)

Answer 2

c) x²-y²-4x+4

=(\(x^2-4x+4\))\(-y^2\)

=\(\left(x-2\right)^2\) \(-y^2\)

=(\(x-y-2\)) \(\left(x+y-2\right)\)

 

Answer 3

a)6x³y-9x²y²+3xy

=\(3xy\left(2x^2-3xy+1\right)\)

Answer 4

a: \(6x^3y-9x^2y^2+3xy\)

\(=3xy\left(2x^2-3xy+1\right)\)

b: \(x^2-3x+xy-3y\)

\(=x\left(x-3\right)+y\left(x-3\right)\)

\(=\left(x-3\right)\left(x+y\right)\)

c: \(x^2-y^2-4x+4\)

\(=\left(x-2\right)^2-y^2\)

\(=\left(x-2-y\right)\left(x-2+y\right)\)