a) \(\dfrac{x}{-15}=\dfrac{-60}{3}\)
\(\Rightarrow x:\left(-15\right)=-20\)
\(\Rightarrow x=-20\cdot\left(-15\right)\)
\(\Rightarrow x=300\)
b) \(\dfrac{3,5}{15}=\dfrac{-2}{x}\)
\(\Rightarrow3,5\cdot x=-2\cdot15\)
\(\Rightarrow3,5x=-30\)
\(\Rightarrow x=-30:3,5\)
\(\Rightarrow x=-\dfrac{60}{7}\)
a: \(\dfrac{x}{-15}=-\dfrac{60}{3}\)
=>\(\dfrac{x}{15}=\dfrac{60}{3}\)
=>\(\dfrac{x}{15}=20\)
=>\(x=20\cdot15=300\)
b: \(\dfrac{3.5}{15}=\dfrac{-2}{x}\)
=>\(x=\dfrac{15\cdot\left(-2\right)}{3,5}=-\dfrac{30}{3,5}=-\dfrac{60}{7}\)
a)
\(\dfrac{x}{-15}=\dfrac{-60}{3}\\ \\ \\ \\ \Rightarrow\dfrac{x}{-15}=-20\\ \\ \\ \\ \Rightarrow x=-20.\left(-15\right)=300\)
Vậy x=300
b)
\(\dfrac{3,5}{15}=\dfrac{-2}{x}\\ \\ \\ \\ \Rightarrow x=-2:\dfrac{3,5}{15}=-\dfrac{30}{3,5}=-\dfrac{300}{35}=-\dfrac{60}{7}\)
Vậy x=\(-\dfrac{60}{7}\)
