Question

Máy mình chụp đề hơi mờ, các bạn thông cảm nha

Answer 1

Bài 10:

a: \(\frac{\left(\frac23\right)^3\cdot\left(-\frac34\right)^2\cdot\left(-1\right)^5}{\left(\frac25\right)^2\cdot\left(-\frac{5}{12}\right)^2}\)

\(=\frac{\frac{2^3}{3^3}\cdot\frac{3^2}{4^2}\cdot\left(-1\right)}{\frac{2^2}{5^2}\cdot\frac{5^2}{12^2}}=\frac{-\frac{2^3}{2^4\cdot3}}{\frac{2^2}{2^2\cdot6^2}}=\frac{-1}{2\cdot3}:\frac{1}{6^2}=-\frac16\cdot36=-6\)

b: \(\frac{6^6+6^3\cdot3^3+3^6}{-73}=\frac{3^6\cdot2^6+3^3\cdot2^3\cdot3^3+3^6}{-73}\)

\(=\frac{3^6\left(2^6+2^3+1\right)}{-73}=-3^6=-729\)