`(-(5)/(3))^{3}<x< -(24)/(35).(-5)/(6)`
`->((-5)^{3})/(3^{3})<x< (24.5)/(35.6)`
`->-(125)/(27)<x<(4)/(7)`
(−53)3<x<−2435.−56(-53)3<x<-2435.-56
(−5)333<x<24.535.6→(-5)333<x<24.535.6
−12527<x<47
Ta có: \(\left(-\dfrac{5}{3}\right)^3< x< \dfrac{-24}{35}\cdot\dfrac{-5}{6}\)
\(\Leftrightarrow\dfrac{-125}{27}< x< \dfrac{4}{7}\)