Question

giúp mình câu b,c

Answer 1

a: Ta có: \(P=\left(\dfrac{1}{\sqrt{x}-1}+\dfrac{1}{\sqrt{x}+1}\right)+\dfrac{x+1}{x-1}\)

\(=\dfrac{\sqrt{x}+1+\sqrt{x}-1+x+1}{\left(\sqrt{x}-1\right)\cdot\left(\sqrt{x}+1\right)}\)

\(=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}\)