1: \(\Leftrightarrow x^2+6x+9-x^2+3x+10=-26\)
=>9x=-45
hay x=-5
2: \(=\dfrac{18-4x}{\left(x-3\right)\left(x+3\right)}+\dfrac{5x-15}{\left(x-3\right)\left(x+3\right)}=\dfrac{18-4x+5x-15}{\left(x-3\right)\left(x+3\right)}=\dfrac{x+3}{\left(x-3\right)\left(x+3\right)}=\dfrac{1}{x-3}\)
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1: ⇔x2+6x+9−x2+3x+10=−26⇔x2+6x+9−x2+3x+10=−26
=>9x=-45
hay x=-5
2:
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